Attach a txt file in Python smtplib

Question

I am sending a plain text email as follows:

import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

def send_message():
    msg = MIMEMultipart('alternative')
    s = smtplib.SMTP('smtp.sendgrid.net', 587)
    s.login(USERNAME, PASSWORD)

    toEmail, fromEmail = to@email.com, from@email.com
    msg['Subject'] = 'subject'
    msg['From'] = fromEmail
    body = 'This is the message'

    content = MIMEText(body, 'plain')
    msg.attach(content)
    s.sendmail(fromEmail, toEmail, msg.as_string())

In addition to this message, I would like to attach a txt file, 'log_file.txt'. How would I attach a txt file here?

score 45 · Accepted Answer · edited Jul 27 '15 at 09:54

45

The same way, using msg.attach:

from email.mime.text import MIMEText

filename = "text.txt"
f = file(filename)
attachment = MIMEText(f.read())
attachment.add_header('Content-Disposition', 'attachment', filename=filename)           
msg.attach(attachment)

edited Jul 27 '15 at 09:54

Community

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answered Mar 02 '12 at 23:44

Mariusz Jamro

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As a side note, I had to attach the content *after* the attachment or it the plain text in the body wasn't showing. – David542 Mar 03 '12 at 00:17
email.mime.text works for me but email.MIMEText not – Jerry T Jan 16 '15 at 04:01

Edvard Rejthar · Answer 2 · 2020-06-01T19:03:49.560

Since Python3.6, I would recommend start using EmailMessage instead of MimeMultipart. Fewer imports, fewer lines, no need to put the recipients both to the message headers and to the SMTP sender function parameter.

import smtplib
from email.message import EmailMessage

msg = EmailMessage()
msg["From"] = FROM_EMAIL
msg["Subject"] = "Subject"
msg["To"] = TO_EMAIL
msg.set_content("This is the message body")
msg.add_attachment(open(filename, "r").read(), filename="log_file.txt")

s = smtplib.SMTP('smtp.sendgrid.net', 587)
s.login(USERNAME, PASSWORD)
s.send_message(msg)

Even better is to install library envelope by pip3 install envelope that's aim is to handle many things in a very intuitive manner:

from envelope import Envelope
from pathlib import Path

Envelope()\
    .from_(FROM_EMAIL)\
    .subject("Subject")\
    .to("to")\
    .message("message")\
    .attach(Path(filename))\
    .smtp("smtp.sendgrid.net", 587, USERNAME, PASSWORD)\
    .send()

msg.add_attachment(open('log_file.txt', "r", encoding="utf8").read()) to avoid decode error for box / table chars. — Tim Hallbeck, Mar 21 '22 at 20:56

score 1 · Answer 3 · answered Jan 24 '18 at 08:15

It works for me

sender = 'spider@fromdomain.com'
receivers = 'who'

msg = MIMEMultipart()
msg['Subject'] = 'subject'
msg['From'] = 'spider man'
msg['To'] = 'who@gmail.com'
file='myfile.xls'

msg.attach(MIMEText("Labour"))
attachment = MIMEBase('application', 'octet-stream')
attachment.set_payload(open(file, 'rb').read())
encoders.encode_base64(attachment)
attachment.add_header('Content-Disposition', 'attachment; filename="%s"' % os.path.basename(file))
msg.attach(attachment)

print('Send email.')
conn.sendmail(sender, receivers, msg.as_string())
conn.close()

Attach a txt file in Python smtplib

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