open a url on click of ok button in android

Question

I have to open a URL on Click of OK Button in a view. Can someone tell how to do this?

Use [HttpUrlConnection](http://developer.android.com/reference/java/net/HttpURLConnection.html). — Harry Joy, Feb 08 '11 at 06:32
public void openWebURL( String inURL ) { Intent browse = new Intent( Intent.ACTION_VIEW , Uri.parse( inURL ) ); startActivity( browse ); } — Tushar, Feb 08 '11 at 06:34
@tushar: have you tried it? i think it should work properly. do you get any error while running this code? — Harry Joy, Feb 08 '11 at 06:44
try this way http://www.vogella.de/articles/AndroidIntent/article.html — Givantha Kalansuriya, Aug 28 '11 at 16:21

score 293 · Accepted Answer · edited Jul 20 '15 at 10:08

293

On Button click event write this:

Uri uri = Uri.parse("http://www.google.com"); // missing 'http://' will cause crashed
Intent intent = new Intent(Intent.ACTION_VIEW, uri);
startActivity(intent);

that open the your URL.

edited Jul 20 '15 at 10:08

thanhbinh84

17,876
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answered Feb 08 '11 at 06:44

Parag Chauhan

35,760
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95

12

OR `startActivity(new Intent(Intent.ACTION_VIEW,Uri.parse("http://www.google.com"))` – Chris - Jr May 29 '17 at 00:28
@Chris-Jr you have missed the last parenthesis i.e. ) – Muhammad Noman Apr 19 '19 at 12:45
How is this different from opening a webview item? – Ian Jun 06 '21 at 00:50

score 9 · Answer 2 · answered Jun 01 '17 at 12:36

    Button imageLogo = (Button)findViewById(R.id.iv_logo);
    imageLogo.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub
            String url = "http://www.gobloggerslive.com";

            Intent i = new Intent(Intent.ACTION_VIEW);
            i.setData(Uri.parse(url));
            startActivity(i);
        }
    });

score 4 · Answer 3 · answered Jun 26 '17 at 20:04

4

You can use the below method, which will take your target URL as the only input (Don't forget http://)

void GoToURL(String url){
    Uri uri = Uri.parse(url);
    Intent intent= new Intent(Intent.ACTION_VIEW,uri);
    startActivity(intent);
}

answered Jun 26 '17 at 20:04

Dogu Deniz Ugur

199
12

score 2 · Answer 4 · answered Aug 22 '19 at 02:34

String url = "https://www.murait.com/";
if (url.startsWith("https://") || url.startsWith("http://")) {
    Uri uri = Uri.parse(url);
    Intent intent = new Intent(Intent.ACTION_VIEW, uri);
    startActivity(intent);
}else{
    Toast.makeText(mContext, "Invalid Url", Toast.LENGTH_SHORT).show();
}

You have to check that the URL is valid or not. If URL is invalid application may crash so that you have to check URL is valid or not by this method.

score 2 · Answer 5 · answered Mar 26 '21 at 06:33

2

Add this code to your OK button click listener.

startActivity(Intent(Intent.ACTION_VIEW, Uri.parse("http://www.google.com")))

answered Mar 26 '21 at 06:33

Ghayas

1,266
10
17

score 1 · Answer 6 · answered Apr 04 '18 at 13:39

create an intent and set an action for it while passing the url to the intent

yourbtn.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                String theurl = "http://google.com";
                Uri urlstr = Uri.parse(theurl);
                Intent urlintent = new Intent();
                urlintent.setData(urlstr);
                urlintent.setAction(Intent.ACTION_VIEW);
                startActivity(urlintent);

score 1 · Answer 7 · answered Jan 06 '20 at 19:05

1

No need for any Java or Kotlin code to make it a clickable link, now you just need to follow given below code. And you can also link text color change by using textColorLink.

<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:autoLink="web"
android:textColorLink="@color/white"/>

answered Jan 06 '20 at 19:05

Abdul Mateen

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Interesting, but it doesn't allow longClicks to override the autoLink. – Michael Plischke Apr 30 '23 at 23:02

score 1 · Answer 8 · answered Jun 23 '22 at 00:20

1

The following code worked perfectly for me.

fun Context.goToUrl(url: String) {
if (url.startsWith("https://") || url.startsWith("http://")) {
    val uriUrl = Uri.parse(url)
    val launchBrowser = Intent(Intent.ACTION_VIEW, uriUrl)
    startActivity(launchBrowser)

} else {
      Toast.makeText(this, "Invalid Url", Toast.LENGTH_SHORT).show()
}

}

call it in your actvity or fragment

requireContext().goToUrl("https://"+"something")

answered Jun 23 '22 at 00:20

Kwesi Welbred

69
1
5

Note, I combined @Mahamud and Sojitra to arrive at this solution. – Kwesi Welbred Jun 23 '22 at 00:24

score 0 · Answer 9 · answered Dec 15 '21 at 10:44

0

 private fun goToUrl(url: String) {
        val uriUrl = Uri.parse(url)
        val launchBrowser = Intent(Intent.ACTION_VIEW, uriUrl)
        startActivity(launchBrowser)
    }

answered Dec 15 '21 at 10:44

Raihan Mahamud

47
8

Can you please give some explanation? – Tugay Dec 18 '21 at 20:31

open a url on click of ok button in android

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