I am trying to zip the folders which are created as output of my jenkins pipeline job using pipeline script. By googling i came to know the Jenkins
Pipeline Utility Steps - zip zipFile
https://jenkins.io/doc/pipeline/steps/pipeline-utility-steps/#code-zip-code-create-zip-file to zip folders/files but could not get exact pipeline syntax to zip.
In my job workspace, I have a folder by name 'Test' which has 2 sub folders as 'Test1', 'Test2'. Each sub folder will have .dll files. So, I would like to zip entire 'Test' folder with all subfolder.
node(Jenkinks_1)
{
echo "ZIP"
zip zipFile: 'Test.zip', dir:'C:\\workspace\\Build_Sample\\Test'
echo "END - ZIP"
}
Below are the Console Output from Jenkins:
Started by user XXXXX
[Pipeline] node
Running on Jenkinks_1 in C:\workspace\Build_Sample
[Pipeline] {
[Pipeline] echo
ZIP
[Pipeline] echo
END - ZIP
[Pipeline] }
[Pipeline] // node
[Pipeline] End of Pipeline
Finished: SUCCESS
Looking for some guidance to zip the folders using pipeline syntax. Appreciate your inputs.
I wanted to zip some files as output of my jenkins pipeline job