Zip a directory in Jenkins Pipeline

Question

I keep getting this error: "No signature of method: zip.call()"

This is the code i am running in Jenkins pipeline :

pipeline {
   agent any
   stages {
       stage("test..")
       {
            steps
            {
             zip dir: '', glob: '', zipFile: 'testz.zip'
            }
        }
    }
}

I have the zip step appear in sample steps in pipeline syntax, so not sure why this failing. I need to zip my source code folder.

Pipeline Utility Steps plugins is installed :

Have you installed the "pipeline utility steps" plugin? https://stackoverflow.com/a/48386777/6509 — tim_yates, Jun 17 '18 at 17:05

score 3 · Answer 1 · answered Nov 14 '18 at 14:41

3

Try this:

pipeline {
   agent any
   stages {
       stage("test.."){
          steps{
             script{
                    zip archive: true, dir: '', glob: '', zipFile: 'testz.zip'
             }
          }
       }
    }
}

Reference: https://jenkins.io/doc/pipeline/steps/pipeline-utility-steps/#zip-create-zip-file

answered Nov 14 '18 at 14:41

Chandara Chea

289
3
11

Does this work when we run a pipeline using a container ? – raviTeja May 13 '22 at 06:40

score 0 · Answer 2 · answered Jun 18 '18 at 15:38

Try to wrap zip step with script {}

pipeline {
    agent any
    stages {
        stage("test..") {
            steps {
                script {
                    zip dir: '', glob: '', zipFile: 'testz.zip'
                }
            }
        }
    }
}

Zip a directory in Jenkins Pipeline

2 Answers2