How can I multiply a vector and a matrix in tensorflow without reshaping?

Question

This:

import numpy as np
a = np.array([1, 2, 1])
w = np.array([[.5, .6], [.7, .8], [.7, .8]])

print(np.dot(a, w))
# [ 2.6  3. ] # plain nice old matrix multiplication n x (n, m) -> m

import tensorflow as tf

a = tf.constant(a, dtype=tf.float64)
w = tf.constant(w)

with tf.Session() as sess:
    print(tf.matmul(a, w).eval())

results in:

C:\_\Python35\python.exe C:/Users/MrD/.PyCharm2017.1/config/scratches/scratch_31.py
[ 2.6  3. ]
# bunch of errors in windows...
Traceback (most recent call last):
  File "C:\_\Python35\lib\site-packages\tensorflow\python\framework\common_shapes.py", line 671, in _call_cpp_shape_fn_impl
    input_tensors_as_shapes, status)
  File "C:\_\Python35\lib\contextlib.py", line 66, in __exit__
    next(self.gen)
  File "C:\_\Python35\lib\site-packages\tensorflow\python\framework\errors_impl.py", line 466, in raise_exception_on_not_ok_status
    pywrap_tensorflow.TF_GetCode(status))
tensorflow.python.framework.errors_impl.InvalidArgumentError: Shape must be rank 2 but is rank 1 for 'MatMul' (op: 'MatMul') with input shapes: [3], [3,2].

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "C:/Users/MrD/.PyCharm2017.1/config/scratches/scratch_31.py", line 14, in <module>
    print(tf.matmul(a, w).eval())
  File "C:\_\Python35\lib\site-packages\tensorflow\python\ops\math_ops.py", line 1765, in matmul
    a, b, transpose_a=transpose_a, transpose_b=transpose_b, name=name)
  File "C:\_\Python35\lib\site-packages\tensorflow\python\ops\gen_math_ops.py", line 1454, in _mat_mul
    transpose_b=transpose_b, name=name)
  File "C:\_\Python35\lib\site-packages\tensorflow\python\framework\op_def_library.py", line 763, in apply_op
    op_def=op_def)
  File "C:\_\Python35\lib\site-packages\tensorflow\python\framework\ops.py", line 2329, in create_op
    set_shapes_for_outputs(ret)
  File "C:\_\Python35\lib\site-packages\tensorflow\python\framework\ops.py", line 1717, in set_shapes_for_outputs
    shapes = shape_func(op)
  File "C:\_\Python35\lib\site-packages\tensorflow\python\framework\ops.py", line 1667, in call_with_requiring
    return call_cpp_shape_fn(op, require_shape_fn=True)
  File "C:\_\Python35\lib\site-packages\tensorflow\python\framework\common_shapes.py", line 610, in call_cpp_shape_fn
    debug_python_shape_fn, require_shape_fn)
  File "C:\_\Python35\lib\site-packages\tensorflow\python\framework\common_shapes.py", line 676, in _call_cpp_shape_fn_impl
    raise ValueError(err.message)
ValueError: Shape must be rank 2 but is rank 1 for 'MatMul' (op: 'MatMul') with input shapes: [3], [3,2].

Process finished with exit code 1

(not sure why the same exception is raised inside its handling)

The solution suggested in Tensorflow exception with matmul is reshaping the vector to a matrix but this leads to needlessly complicated code - is there still no other way to multiply a vector with a matrix?

Incidentally using expand_dims (as suggested in the link above) with default arguments raises a ValueError - that's not mentioned in the docs and defeats the purpose of having a default argument.

Answer 1

tf.einsum gives you the ability to do exactly what you need in concise and intuitive form:

with tf.Session() as sess:
    print(tf.einsum('n,nm->m', a, w).eval())
    # [ 2.6  3. ] 

You even get to write your comment explicitly n x (n, m) -> m. It is more readable and intuitive in my opinion.

My favorite use case is when you want to multiply a batch of matrices with a weight vector:

n_in = 10
n_step = 6
input = tf.placeholder(dtype=tf.float32, shape=(None, n_step, n_in))
weights = tf.Variable(tf.truncated_normal((n_in, 1), stddev=1.0/np.sqrt(n_in)))
Y_predict = tf.einsum('ijk,kl->ijl', input, weights)
print(Y_predict.get_shape())
# (?, 6, 1)

So you can easily multiply weights over all batches with no transformations or duplication. This you can not do by expanding dimensions like in other answer. So you avoid the tf.matmul requirement to have matching dimensions for batch and other outer dimensions:

The inputs must, following any transpositions, be tensors of rank >= 2 where the inner 2 dimensions specify valid matrix multiplication arguments, and any further outer dimensions match.

Answer 2

Matmul was coded for rank two or greater tensors. Not sure why to be honest as numpy has it such that it allows for matrix vector multiplication as well.

import numpy as np
a = np.array([1, 2, 1])
w = np.array([[.5, .6], [.7, .8], [.7, .8]])

print(np.dot(a, w))
# [ 2.6  3. ] # plain nice old matix multiplication n x (n, m) -> m
print(np.sum(np.expand_dims(a, -1) * w , axis=0))
# equivalent result [2.6, 3]

import tensorflow as tf

a = tf.constant(a, dtype=tf.float64)
w = tf.constant(w)

with tf.Session() as sess:
  # they all produce the same result as numpy above
  print(tf.matmul(tf.expand_dims(a,0), w).eval())
  print((tf.reduce_sum(tf.multiply(tf.expand_dims(a,-1), w), axis=0)).eval())
  print((tf.reduce_sum(tf.multiply(a, tf.transpose(w)), axis=1)).eval())

  # Note tf.multiply is equivalent to "*"
  print((tf.reduce_sum(tf.expand_dims(a,-1) * w, axis=0)).eval())
  print((tf.reduce_sum(a * tf.transpose(w), axis=1)).eval())

Answer 3

You can use tf.tensordot and set axes=1. For the simple operation of a vector times a matrix, this is a bit cleaner than tf.einsum

tf.tensordot(a, w, 1)