Sum of two n bit numbers (n<=255) in 8085 microprocessor

Asked Jan 01 '16 at 12:36

Active Jan 04 '16 at 17:32

Viewed 629 times

LDA 2000h ; Store the no of byte that each number consists of in memory location 2000h.
MOV C A
MOV B A
LXI D 5000h
LXI H 2001h
STC
CMC
LOOP1: MOV A M
SHLD 7000h
LOOP: INX H
DCR C
JNZ LOOP
ADC M
STAX D
LHLD 7000h
LDA 2000h
MOV C A
INX D
INX H
DCR B
JNZ LOOP1
HLT

This is my code for the above mentioned problem. What would be more efficient algorithm to do so?

edited Jan 04 '16 at 17:32

asked Jan 01 '16 at 12:36

Soumya Kanti Naskar

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I guess you work in a museum. But format the question a bit better – Ed Heal Jan 01 '16 at 12:38
@EdHeal He come here to get help – Saiful Azad Jan 01 '16 at 12:40
It was a joke. But the question could do with being formatted better – Ed Heal Jan 01 '16 at 12:41
What do mean by working in a museum and what kind of formatting do you want?? @Ed Heal – Soumya Kanti Naskar Jan 01 '16 at 12:48
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The formatting is a lot better after the edit. The 8085 processor is a cira. 1970 and 8 bit – Ed Heal Jan 01 '16 at 12:49
I can't get you. Is there any solution of my problem? – Soumya Kanti Naskar Jan 01 '16 at 12:52

Sum of two n bit numbers (n<=255) in 8085 microprocessor

0 Answers0