System.out.print of string without 'ln'

Question

I have a byte array which looks like this:

[0, 0, 0, 0, 0, 0, 0, 0, 122, 98, 117, 54, 46, 0, 0, 115, 122, 42, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 116, 121, 116, 117, 108, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 32, 107, 111, 98, 105, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 122, 42, 109, 111, 119, 40, 0, 0, 0, 0, 0, 0, 107, 111, 98, 0, 0, 0, 0, 0, 98, 111, 40]

I wanted to print it as a string, so I wrote the following code:

System.out.println(new String(byteArray));

but there is no output. Next, I tried the following code:

for (byte b : byteArray) {
    System.out.print((char) b);
}

but again there is no output. But when I tried the following code:

for (byte b : byteArray) {
    System.out.println((char) b);
}

I was able to see the values.

My question is, why can't I create a string or why did the first printing of values from byteArray fail?

well, they are all giving the same result in my computer.. the only difference is the `ln` gives me many lines.. — Yohanes Khosiawan 许先汉, Mar 19 '14 at 02:26

score 0 · Answer 1 · answered Mar 19 '14 at 02:23

0

try this

System.out.println(Arrays.toString(byteArray));

answered Mar 19 '14 at 02:23

Evgeniy Dorofeev

133,369
30
199
275

score 0 · Answer 2 · answered Mar 19 '14 at 02:23

Try this.

byte[] bytes = new byte[]{0, 0, 0, 0, 0, 0, 0, 0, 122, 98, 117, 54, 46, 0, 0, 115, 122, 42, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 116, 121, 116, 117, 108, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 32, 107, 111, 98, 105, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 122, 42, 109, 111, 119, 40, 0, 0, 0, 0, 0, 0, 107, 111, 98, 0, 0, 0, 0, 0, 98, 111, 40};
System.out.println(new String(bytes));

score 0 · Answer 3 · edited Dec 18 '20 at 22:36

0

Your byte array is mostly non printable characters, with a few random letters mixed in. But all you need is:

String myString = new String(byteArray);

which will give you a valid string.

Try out the following code, as maybe it will better illustrate the issue your having:

for (char c : new String(byteArray).toCharArray()) {
    System.out.printf("Character: %s Hex: %02x \n", c, (int) c);
}

edited Dec 18 '20 at 22:36

answered Mar 19 '14 at 02:30

James Kidd

444
4
8

I want to convert my byte array into characters. But after using what you suggested, nothing appears – Rop Mar 19 '14 at 08:09
Edited my answer after your clarification, hopefully that solves it for you. – James Kidd Mar 19 '14 at 09:05

score 0 · Answer 4 · answered Dec 19 '20 at 16:31

You can use a String(byte[],Charset) constructor and specify a Charset to be used to decode this array of bytes:

System.out.println(new String(byteArray, StandardCharsets.UTF_8));

In most cases, StandardCharsets.UTF_8 is a default charset.

System.out.print of string without 'ln'

4 Answers4

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