76

I am trying to set up a view's layer properties via IB. Everything works except for color of the border (property layer.borderColor):

enter image description here

I remember running into this problem a year ago and I ended up doing it programatically. And still, I can do this programmatically, but I am curious why the layer.borderColorproperty never works via interface builder. I don't want to import QuartzCore, and then write extra line of code just because of this, seems like an overkill.

Bartłomiej Semańczyk
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0xSina
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    "write extra line of code just because of this, seems like an overkill" - your app must be containing at most 10 lines of code then (with the C standard headers included) :P –  Feb 09 '13 at 22:22
  • @H2CO3 lol...i just don't like writing code that i don't have to – 0xSina Feb 09 '13 at 23:33
  • I've made this mistake in the past.. I hope you are aware of it.. otherwise check the first answer from this: http://stackoverflow.com/questions/3980251/user-defined-runtime-attributes-in-ib-for-iphone-not-working – chuthan20 Feb 10 '13 at 22:20
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    You can do this with a proxy property! See my answer in http://stackoverflow.com/questions/12301256/is-it-possible-to-set-uiview-border-properties-from-interface-builder – Peter DeWeese Aug 01 '13 at 12:22

16 Answers16

83

It's possible to do this, but it's not a built-in feature. This is because the Color type in the User Defined Runtime Attributes panel creates a UIColor, but layer.borderColor holds a CGColorRef type. Unfortunately, there's no way to assign a CGColorRef type in Interface Builder.

However, this is possible through a proxy property. See Peter DeWeese's answer to a different question for a possible solution to this problem. His answer defines a category that allows a proxy color to be set through Interface Builder.

Community
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mopsled
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  • A computed property is not required. You can find an answer here that shows how to get this to work in a storyboard with layer.borderColor. https://stackoverflow.com/a/72914638/1058199 – Alex Zavatone Jul 08 '22 at 16:56
52

You have to create Category for CALayer:

CALayer+UIColor.h

#import <QuartzCore/QuartzCore.h>
#import <UIKit/UIKit.h>

@interface CALayer(UIColor)

// This assigns a CGColor to borderColor.
@property(nonatomic, assign) UIColor* borderUIColor;

@end

CALayer+UIColor.m

#import "CALayer+UIColor.h"

@implementation CALayer(UIColor)

- (void)setBorderUIColor:(UIColor*)color {
    self.borderColor = color.CGColor;
}

- (UIColor*)borderUIColor {
    return [UIColor colorWithCGColor:self.borderColor];
}

@end

And then in User Defined Runtime attributes You can use it as it is on image below:

enter image description here

For Swift it is much more simple:

import QuartzCore

extension CALayer {
    @IBInspectable var borderUIColor: UIColor? {
        get {
            guard let borderColor = borderColor else { return nil }
            return UIColor(cgColor: borderColor)
        }
        
        set {
            borderColor = newValue?.cgColor
        }
    }
}

Then in Xcode you can use it like this:

enter image description here

Once you choose something it is automatically added to your runtime attributes.

halfer
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Bartłomiej Semańczyk
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26

Copy and paste this class:

import UIKit

@IBDesignable class BorderView : UIView {
    @IBInspectable var borderColor: UIColor = .clear {
        didSet {
        layer.borderColor = borderColor.cgColor
        }
    }

    @IBInspectable var borderWidth: CGFloat = 0 {
        didSet {
            layer.borderWidth = borderWidth
        }
    }

    @IBInspectable var cornerRadius: CGFloat = 0 {
        didSet {
            layer.cornerRadius = cornerRadius
        }
    }
}

Now in Interface Builder, go to the Identity inspector and set your view as a CustomView class.

After that, check out your Attributes Inspector:

Attributes inspector with the new IBInspectable options

No need to mess around with user defined runtime attributes anymore. And your changes will also show up on the canvas!

Tamás Sengel
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etayluz
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20

My two cents for porting Bartłomiej Semańczyk's answer to Swift:

Create an extension for CALayer in your view controller:

import UIKit

extension CALayer {
    func borderUIColor() -> UIColor? {
        return borderColor != nil ? UIColor(CGColor: borderColor!) : nil
    }

    func setBorderUIColor(color: UIColor) {
        borderColor = color.CGColor
    }
}
Sahil Kapoor
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Eduardo
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11

Use IBDesignable instead of Runtime Attributes it is more clear.

Put this code in any class and edit the properties direct on the storyboard.

import UIKit

@IBDesignable extension UIView {
    @IBInspectable var borderColor:UIColor? {
        set {
            layer.borderColor = newValue!.CGColor
        }
        get {
            if let color = layer.borderColor {
                return UIColor(CGColor:color)
            }
            else {
                return nil
            }
        }
    }
    @IBInspectable var borderWidth:CGFloat {
        set {
            layer.borderWidth = newValue
        }
        get {
            return layer.borderWidth
        }
    }
    @IBInspectable var cornerRadius:CGFloat {
        set {
            layer.cornerRadius = newValue
            clipsToBounds = newValue > 0
        }
        get {
            return layer.cornerRadius
        }
    }
}
etayluz
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FedeH
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  • This saves a major headache when you're applying these to several items. Slick little tidbit. – Haligen Jul 15 '16 at 16:47
  • I'm sorry but this doesn't work. I have just tried it myself. @IBDesignable doesn't work on extensions of UIView. http://stackoverflow.com/questions/29906855/can-you-add-ibdesignable-properties-to-uiview-using-categories-extensions – etayluz Aug 20 '16 at 16:07
  • Just tried with some tiny upper/lower case problem with Swift 3.0. Shame that I did not know this before. – Michael Shang Dec 28 '16 at 20:34
  • As of Xcode 9 & Swift 3, this actually does work at runtime. It just doesn't display the changes in the interface builder. – Harrison Smith Aug 19 '18 at 08:06
5

Here's a quick way to overcome this. Categories...

@interface UIView (IBAppearance)

@property (nonatomic, strong) UIColor *borderColor;

@end

You don't have to store it, it's just nice so you can query later. The important thing is taking the value and assigning the UIColor's CGColor to the layer.

#import <objc/runtime.h>

#define BORDER_COLOR_KEYPATH @"borderColor"

@implementation UIView (IBAppearance)

- (void)setBorderColor:(UIColor *)borderColor {
    UIColor *bc = objc_getAssociatedObject(self, BORDER_COLOR_KEYPATH);
    if(bc == borderColor) return;
    else {
        objc_setAssociatedObject(self, BORDER_COLOR_KEYPATH, borderColor, OBJC_ASSOCIATION_RETAIN_NONATOMIC);
        self.layer.borderColor = [borderColor CGColor];
    }
}

- (UIColor *)borderColor {
    return objc_getAssociatedObject(self, BORDER_COLOR_KEYPATH);
}

@end

Of course, in the Interface Builder you're not setting the value on layer.borderColor, rather just on borderColor.

Aage
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bainfu
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  • i think there is no need to use associated objects because something may happen and your borderColor will be out of sync with layer.borderColor. just return [UIColor colorWithCGColor:self.layer.borderColor] – storoj Nov 17 '13 at 00:09
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    You're absolutely right @storoj. It's a pattern we use for adding properties and being able to store them using categories. It's misapplied here. – bainfu Jan 22 '14 at 21:47
5

In Swift, you can extend the UIButton class and add an @IBInspectable that will enable you to select a color from storyboard and set it's color (with width of 1 which can be changed). Add this at the end of your view controller:

extension UIButton{
    @IBInspectable var borderColor: UIColor? {
        get {
            return UIColor(CGColor: layer.borderColor!)
        }
        set {
            layer.borderColor = newValue?.CGColor
            layer.borderWidth = 1
        }
    }
}
Tunaki
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HusseinB
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4

In order to make CALayer KVC-compliant for the property borderColorFromUIColor, simply implement the

layer.borderColorFromUIColor=[UIColor red];

This link have awnser

Hiren
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Mohit
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2

I met the same issue, I worked around it by creating a custom button class:

class UIButtonWithRoundBorder: UIButton {

required init?(coder aDecoder: NSCoder) {
    super.init(coder: aDecoder)
    self.layer.cornerRadius = 6
    self.layer.borderWidth = 1
    self.layer.borderColor = UIColor.whiteColor().CGColor
    self.clipsToBounds = true
}

}

Then in IB, change the type from "UIButton" to "UIButtonWithRoundBorder".

Simple and handy too. :)

RainCast
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2

swift4

extension CALayer {

  open override func setValue(_ value: Any?, forKey key: String) {

    /// If key is borderColor, and the value is the type of a UIColor.
     if key == "borderColor" , let color = value as? UIColor {

        /// After converting UIColor to CGColor, call the system method.
        return super.setValue(color.cgColor, forKey: key)
     }

     super.setValue(value, forKey: key)
   }
}
zheng
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1

borderColor will not work UNLESS the borderWidth property of the layer is set to a value greater than 0.

Swift 3:

button.layer.borderColor = UIColor.white.cgColor
button.layer.borderWidth = 1.0 // Default value is 0, that's why omitting this line will not make the border color show.
Malloc
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    Your answer has nothing to do with the question. The poster said he knows how to do it programmatically. Also, you can see that he already set the borderWidth to be >1 in his screenshot. He asked about doing this specifically in IB. – jungledev Jul 21 '17 at 17:35
1

You can set a value for the "borderColor" key in the XIB and use:

extension UIView {

    open override func setValue(_ value: Any?, forKey key: String) {
        guard key == "borderColor", let color = value as? UIColor else {
            super.setValue(value, forKey: key)
            return
        }

        layer.borderColor = color.cgColor
    }
}
  • Excellent. This works in Xcode 13.4 with layer.borderColor and not needing to use a computed property. Just needed an import UIKit and it works as written. – Alex Zavatone Jul 08 '22 at 00:51
  • my only corrections were to change UIView to CGLayer and to change layer.borderColor to self.borderColor. Your answer is the only solution I have seen that answers this question as asked. Wonderful work. – Alex Zavatone Jul 08 '22 at 16:41
0

I think it may be because you have masksToBounds set to YES. I don't think the border is drawn within the bounds of the layer, so it won't be drawn since you're hiding everything outside of its bounds.

Chris C
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  • Hmmmm...not @ my desktop so will experiment with that, but if I set masksToBounds to NO, then I can't have UIImageView rounded/corner radius :( – 0xSina Feb 10 '13 at 19:18
0

You can customise border with 2 methods. First one is this. Just click on the object go to the identity inspector and set the attributes.

enter image description here

Second one is this. make an IBOutlet of required object and put this code in view did load.

@IBOutlet weak var uploadView: UIView!

    override func viewDidLoad() {
        super.viewDidLoad()

        uploadView.layer.cornerRadius = 10
        uploadView.layer.borderWidth = 1.0
        uploadView.layer.borderColor = #colorLiteral(red: 0.08235294118, green: 0.5058823529, blue: 0.9450980392, alpha: 1)
    }
Akbar Khan
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0

Swift 5.2 - Answer of Fede Henze's

@IBDesignable extension UIView {

@IBInspectable var borderColor:UIColor? {
    set {
        layer.borderColor = newValue!.cgColor
    }
    get {
        if let color = layer.borderColor {
            return UIColor(cgColor:color)
        }
        else {
            return nil
        }
    }
}
@IBInspectable var borderWidth:CGFloat {
    set {
        layer.borderWidth = newValue
    }
    get {
        return layer.borderWidth
    }
}
@IBInspectable var cornerRadius:CGFloat {
    set {
        layer.cornerRadius = newValue
        clipsToBounds = newValue > 0
    }
    get {
        return layer.cornerRadius
    }
}
}
Prakash
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0

try this in User Defined Runtime attribute:

  1. Key Path: layer.borderUIColor
  2. type: Color
  3. Value: --you prefered color--
Dilip M
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