waveOut is an API for playing digital sounds in Windows.
Questions tagged [waveout]
52 questions
0
votes
1 answer
Unexpected waveform with waveOut API
I have a problem with the waveOut interface. I want to write a simple class structure where i have a class AudioStream that makes it very simple to have audio output. I have a constructor that takes the following arguments:
AudioStream32(int…
Ruben
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How to initialize WaveOUT API on Win CE running on ARM in C#
I am trying to make work WinOut API on Win CE (ARM) but with the same code
that runs on Windows 7 I am getting MMSYSERR_INVALIDPARAM in the line for buffer preparation.
Win32.MMRESULT hr = Win32.waveOutPrepareHeader(
hWaveOut, ref…
Patrik
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1 answer
How to P/Invoke WaveOut API on Windows CE 6.0 R3
How to P/Invoke WaveOut API on Windows CE 6.0 R3 ?
When I put this
[DllImport("winmm.dll", SetLastError = true, CharSet = CharSet.Auto)]
public static extern MMRESULT waveOutOpen(ref IntPtr hWaveOut, int uDeviceID, ref WAVEFORMATEX lpFormat,…
Patrik
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2 answers
Play .wav with WaveOutOpen(C++)
I need to play audio file(.wav) with waveOutOpen function. I found manual for this. http://www.planet-source-code.com/vb/scripts/ShowCode.asp?txtCodeId=4422&lngWId=3 but I dont know how change this for .wav files. Please help me...
Alexander Mashin
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WaveOut to play wave file to specific channels of the device
I am using WaveOut API for playing the .wav file, using the device capability I am getting the device information. Is there any way to get the channel information (e.g. how the ASIO gives) and need to play two different .wav files to the two…
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2 answers
freeing pwfx after waveOutOpen throws
According to Microsoft documentation:
"You can free this [pwfx] structure immediately after passing it to waveOutOpen."
But this code dosen't seem to agree:
pwfx=new…
lkanab
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