Return from static initializer

Question

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Returning in a static initializer

Is there a way to exit a static initialiser in Java, something like the code below (which does not compile):

public class Test {

    private static int i = 1;

    static {
        if (i == 0) {
            return; // DOESN'T COMPILE
        }
        i = 0;
    }
}

ps: yes I know, the example makes no sense, i == 0 will always be false at this point, but that's not the point!

@Eng.Fouad I don't want to exit, just continue to the rest of the code - the duplicate answers why it is not possible, thanks. — assylias, Apr 02 '12 at 11:58
OK then, use a label on an instance block and break that label. `static{label:{if(i == 0) break label; i = 0}}` — Eng.Fouad, Apr 02 '12 at 12:06

score 2 · Accepted Answer · answered Apr 02 '12 at 11:55

2

A quick and dirty method would be, misusing a for loop and use its break statement for flow control:

static
{
    int i = 0;

    for(;;)
    {
        if(i == 0)
            break;
        // more code
        // more conditions
        // don't forget the final break
        break;
    }
}

answered Apr 02 '12 at 11:55

Neet

3,937
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Using a label is cleaner :) .. I want to +1 this answer, but I'm running out of up-votes for the rest of the day :) – Eng.Fouad Apr 02 '12 at 12:14
2

:-) That's why I said quick and dirty^^ – Neet Apr 02 '12 at 12:16

Return from static initializer

1 Answers1