How do I add space between two variables after a print in Python

Question

I'm fairly new to Python, so I'm trying my hand at some simple code. However, in one of the practices my code is supposed to display some numbers in inches on the left and the conversion of the numbers on the right;

count = 1
conv = count * 2.54
print count, conv

I want the output to be printed with some space between them;

count = 1
conv = count * 2.54
print count,     conv

I can't figure out how to do this. I've searched everywhere, but all I can find are people trying to get rid of space. If someone could just lead me in the right direction, I'd be thankful.

Oh, and I just realized that I'm using Python 2.7, not 3.x. Not sure if this is important.

Óscar López · Accepted Answer · 2012-04-02T00:57:30.277

14

A simple way would be:

print str(count) + '  ' + str(conv)

If you need more spaces, simply add them to the string:

print str(count) + '    ' + str(conv)

A fancier way, using the new syntax for string formatting:

print '{0}  {1}'.format(count, conv)

Or using the old syntax, limiting the number of decimals to two:

print '%d  %.2f' % (count, conv)

edited Apr 02 '12 at 00:57

answered Apr 02 '12 at 00:45

Óscar López

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Neither of those work. The first way gives me a Traceback error, and the second one acts as though it's `print count, conv` – Hebon Apr 02 '12 at 00:52
Fixed the first one, for all of them: you can add as many spaces as you need in between! – Óscar López Apr 02 '12 at 00:58
The first won't work because you can't add an integer to a string, nor a string to a float. To get more space in the second and third examples, just put the required number of spaces between the {0} and the {1} or the %d and %f. – Whatang Apr 02 '12 at 00:59
@Hebon fixed all the examples with two spaces in-between. It's very simple to add the spaces you need, just add them in the middle. Also, fixed the last example for displaying only two decimals – Óscar López Apr 02 '12 at 01:04
I managed to eliminate the Traceback by getting rid of some unused code, however, it's still not working. Using `print str(count) + ' ' + str(conv)` it only mashes them together so that they appear as "12.54". – Hebon Apr 02 '12 at 01:06
Are you sure that you're typing the correct number of spaces in-between? it works, all of them work, you can be sure of it. – Óscar López Apr 02 '12 at 01:08
@ÓscarLópez I think I got it to work. I used `print '{0} {1}'.format(count, conv)`. I believe the issue I was having was some unused code at the begining. When I removed it, it stopped the Traceback issues I was getting, and allowed your suggestion to work. That in itself confuses me though, since all the code did was ask for some unused inputs. – Hebon Apr 02 '12 at 01:13
"Traceback" is not a part of the name of the error. It does not describe the error. Rather, the traceback is the text that is displayed to tell you what happened when the error occurred (it will show you the line of code that failed, and the lines that got you to that point). The error type is on the line that says ": ", like `TypeError: unsupported operand type(s) for +: 'int' and 'str'`. That is a `TypeError`, as it says. – Karl Knechtel Apr 02 '12 at 01:19

score 4 · Answer 2 · edited Jan 11 '22 at 20:49

4

You can do it this way in Python 3:

print(a, b, sep=" ")

edited Jan 11 '22 at 20:49

Tomerikoo

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answered Sep 14 '19 at 04:21

Shravya Mutyapu

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score 4 · Answer 3 · answered Apr 02 '12 at 00:45

4

Use string interpolation instead.

print '%d   %f' % (count,conv)

answered Apr 02 '12 at 00:45

Ignacio Vazquez-Abrams

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That almost works, but now I have extra zeros at the end of my "conv" variable `Inches Centimeters 1 2.540000` – Hebon Apr 02 '12 at 00:55
1

So then tune the `%f` specifier. – Ignacio Vazquez-Abrams Apr 02 '12 at 01:00

Gladius · Answer 4 · 2012-04-02T03:38:46.793

3

Alternatively you can use ljust/rjust to make the formatting nicer.

print "%s%s" % (str(count).rjust(10), conv)

or

print str(count).ljust(10), conv

edited Apr 02 '12 at 03:38

answered Apr 02 '12 at 01:32

Gladius

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I actually like this solution more than the `printf` relatives. It's easier to understand than a `printf` format specifier and does exactly what it says on the tin. – Li-aung Yip Apr 02 '12 at 02:03

score 2 · Answer 5 · answered Apr 02 '12 at 03:42

A quick warning, this a pretty wordy answer.

print is tricky sometimes, I had some problems with it when I first started. What you want is a few spaces in between two variables after you print them right? There's many ways to do this, as shown in the above answers.

This is your code:

count = 1
conv = count * 2.54
print count, conv

It's output is this:

1 2.54

If you want spaces in between, you can do it the naive way by sticking a string of spaces in between them. The variables count and conv need to be converted to string types to concatenate(join) them together. This is done with str().

print (str(count) + "           " + str(conv))
### Provides an output of:
1           2.54

To do this is the newer, more pythonic way, we use the % sign in conjunction with a letter to denote the kind of value we're using. Here I use underscores instead of spaces to show how many there are. The modulo before the last values just tells python to insert the following values in, in the order we provided.

print ('%i____%s' % (count, conv))
### provides an output of:
1____2.54

I used %i for count because it is a whole number, and %s for conv, because using %i in that instance would provide us with "2" instead of "2.54" Technically, I could've used both %s, but it's all good.

I hope this helps!

-Joseph

P.S. if you want to get complicated with your formatting, you should look at prettyprint for large amounts of text such as dictionaries and tuple lists(imported as pprint) as well as which does automatic tabs, spacing and other cool junk.

Here's some more information about strings in the python docs. http://docs.python.org/library/string.html#module-string

This is very informative. Thank you for taking the time to explain it. — Hebon, Apr 03 '12 at 00:23

RomanG · Answer 6 · 2021-12-22T17:03:12.420

If you are trying only to print and not to store variables. You can use sep= parameter in print() function, as below:

print("string", "string", sep="something between them")

space_num = 10

count = 1
conv = count * 2.54
print(count, conv, sep=" "*space_num)

If you want to store values as one variable, so I think it will be best to use f string, as below:

space_num = 10

count = 1
conv = count * 2.54

result = f"{count}{' ' * space_num}{conv}"
print(result)

score 1 · Answer 7 · answered Apr 02 '12 at 01:28

1

This is a stupid/hacky way

print count,    
print conv

answered Apr 02 '12 at 01:28

Cadoo

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score 0 · Answer 8 · edited Aug 26 '16 at 00:14

0

print str(count) + ' ' + str(conv) - This did not work. However, replacing + with , works for me

edited Aug 26 '16 at 00:14

Ronen Ness

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answered Aug 25 '16 at 22:48

Daniel

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score 0 · Answer 9 · answered Oct 28 '16 at 21:50

You should use python Explicit Conversion Flag PEP-3101

'My name is {0!s:10} {1}'.format('Dunkin', 'Donuts')

'My name is Dunkin Donuts'

or

'My name is %-10s %s' % ('Dunkin', 'Donuts')

'My name is Dunkin Donuts'

https://www.python.org/dev/peps/pep-3101/

score 0 · Answer 10 · answered Jul 22 '19 at 14:48

0

A simple way to add the tab would be to use the \t tag.

print '{0} \t {1}'.format(count, conv)

answered Jul 22 '19 at 14:48

Abbas Kagdi

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score 0 · Answer 11 · edited Apr 04 '20 at 11:03

0

print( "hello " +k+ "  " +ln);

where k and ln are variables

edited Apr 04 '20 at 11:03

David Buck

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answered Apr 04 '20 at 10:41

Fring0.5

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How do I add space between two variables after a print in Python

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