Linux batch conversion: Change quality of jpg with convert but keep its name

Question

If I convert my images with

convert -quality 80% *.jpg

It works, but the software changes the file names to the first one it picks. How can I keep the name or even replace the previous image with that of a lower quality.

from the man page: > Mogrify overwrites the original image file, whereas, convert(1) writes to a different image file. — Édouard Lopez, Jan 07 '16 at 17:03

score 90 · Accepted Answer · answered Mar 29 '12 at 16:49

90

Try this instead:

mogrify -quality 80% *.jpg

answered Mar 29 '12 at 16:49

Zsolt Botykai

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score 16 · Answer 2 · edited Jan 07 '16 at 16:59

16

convert command help:

convert input-file [options] output-file

Now a little script to convert all jpg files to 80% quality of original under current directory

for file in *.jpg; do
  convert "$file" -quality 80% "$file"
done;

edited Jan 07 '16 at 16:59

Édouard Lopez

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answered Mar 29 '12 at 16:50

ring bearer

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Useless use of `ls`, as it can be shortened to `for f in *jpg`. And mogrify can work on multiple files at once. – Zsolt Botykai Mar 29 '12 at 17:02
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@ringbearer It's not a great way of doing it. Requires another process, and fails for files with spaces. Apart from that it's a great answer. – Sparhawk Jul 10 '14 at 06:02
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I removed subprocess (backtick), and add quotes to prevent errors – Édouard Lopez Jan 07 '16 at 16:59

score 3 · Answer 3 · answered Mar 07 '19 at 10:56

3

This will work for you.

convert -quality 80% '*.jpg' -set filename:original %t %[filename:original].jpg

answered Mar 07 '19 at 10:56

David Jung

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Linux batch conversion: Change quality of jpg with convert but keep its name

3 Answers3