String measurement with Graphics.MeasureString

Question

Please see my code:

Graphics grfx = Graphics.FromImage(new Bitmap(1, 1));

System.Drawing.Font f = new System.Drawing.Font("Times New Roman", 10, FontStyle.Regular);

const string text1 = "check_space";
SizeF bounds1 = grfx.MeasureString(text1, f);

const string text2 = "check_space ";
SizeF bounds2 = grfx.MeasureString(text2, f);

Assert.IsTrue(bounds1.Width < bounds2.Width); // I have Fail here!

I wonder why my test is failed. Why text with space in tail is NOT greater by width than text without space?

UPDATE: I can understand these both strings are not equal. But as I mentally understand the string with space should be greater by width than the string without space. Don't?

Try with `"check_space."` and `"check_space ."`. They are not equal. — L.B, Mar 27 '12 at 19:44
I already posted the answer below. I'm not sure why you haven't accepted it... — Timmerz, Mar 27 '12 at 20:12
Because it has to pass some time - the system do not permit accept it immediately — Michael Z, Mar 27 '12 at 20:38

score 15 · Accepted Answer · answered Mar 27 '12 at 19:48

you have to tell it to measure trailing spaces, which it does not by default.

Graphics grfx = Graphics.FromImage(new Bitmap(1, 1));

System.Drawing.Font f = new System.Drawing.Font("Times New Roman", 10, FontStyle.Regular);

string text1 = "check_space";
SizeF bounds1 = grfx.MeasureString(text1, f, new PointF(0,0), new StringFormat( StringFormatFlags.MeasureTrailingSpaces ));

string text2 = "check_space ";
SizeF bounds2 = grfx.MeasureString(text2, f, new PointF(0,0), new StringFormat( StringFormatFlags.MeasureTrailingSpaces ) );

Wow! Thaks! I have never heard about this – Michael Z Mar 27 '12 at 20:38 — Michael Z, Mar 27 '12 at 20:38

String measurement with Graphics.MeasureString

1 Answers1