boost, matrix_proxy, const matrix

Question

Giving this:

void foo(const matrix<double>& lol)
{
    matrix_row<matrix<double> > lolwut(lol, 5);
}

error:

no matching function for call to ‘boost::numeric::ublas::matrix_row<boost::numeric::ublas::matrix<double> >::matrix_row(const boost::numeric::ublas::matrix<double>&, size_t&)’

How to unconst the reference given in the function's parameter or which workaround to use? I'm not sure if simple assignment

matrix<double> tmp = lol;

will not have any overhead.

score 2 · Accepted Answer · edited Jan 27 '13 at 19:06

2

Here is how you do this using BOOST_AUTO:

void foo(const matrix<double>& lol)
{
    matrix_row< const matrix<double> > lolwut(lol, 5);
}

The spaces are needed if you are compiling to C++ < 11 otherwise some buggy compilers will interpret it as a right bit-shift (>>) operator

edited Jan 27 '13 at 19:06

Cole Tobin

9,206
15
49
74

answered Aug 23 '12 at 14:21

dats

236
1
10

score 1 · Answer 2 · edited Jan 27 '13 at 19:09

1

Try using BOOST_AUTO.

Code:

BOOST_AUTO(r, row(lol, 5));

edited Jan 27 '13 at 19:09

Yuliy

17,381
6
41
47

answered Mar 19 '12 at 11:23

Anycorn

50,217
42
167
261

It is obvious, thanks! I figured it out right after I questioned. The solution is matrix_row > lolwut((matrix) lol, 5); – Evgeny P. Kurbatov Mar 19 '12 at 13:05

boost, matrix_proxy, const matrix

2 Answers2