Opening an image

Question

I am an idiot. Why can't I read any files?

import java.awt.Image;
import java.io.File;
import java.io.IOException;

import javax.imageio.ImageIO;


public class mainClass {

    public static void main(String[] args) {
        try {
            Image picture = ImageIO.read(new File("picture.png"));
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

}

And the file is in the src folder for sure.

But it throws the exception everytime even though the file is there, no misspellings.

edit: The first sentence was true, I didn't put the image in the root.

yes, it throws the exception everytime. That is all the code I have in the program too. — wokparty, Mar 15 '12 at 00:10
What exception does it throw? Also the src folder doesn't mean that it's going to be found.. it needs to be in the runtime folder. How are you running it? — Roy Truelove, Mar 15 '12 at 00:18
I am using eclipse and I run it from there. All I did was stick the image file in the src folder. — wokparty, Mar 15 '12 at 00:23
The image file should go into the root of your eclipse project, not in the src/ folder. Also please post the stacktrace — Alex, Mar 15 '12 at 00:45
Yeah it worked. My brain told me I tried that 3 hours ago. I obviously didn't. Thanks for the defrag. — wokparty, Mar 15 '12 at 01:29

score 3 · Answer 1 · answered Mar 15 '12 at 06:00

3

Been there as well, know that feeling. Anyway, try print out current working directory and that will tell you exactly where is the application really read from.

try
{
    Image picture = ImageIO.read(new File("picture.png"));
}
catch (IOException e)
{
    String workingDir = System.getProperty("user.dir");
    System.out.println("Current working directory : " + workingDir);
    e.printStackTrace();
}

answered Mar 15 '12 at 06:00

Jasonw

5,054
7
43
48

Relevant reference: [java.io.file docs](http://docs.oracle.com/javase/7/docs/api/java/io/File.html) Also, using `absolute path` (like `/home/Stuff/Pictures/picture.png`) worth a shot. In other hand , it's OS dependent. Note: `File` object has an [`getParent()`](http://docs.oracle.com/javase/7/docs/api/java/io/File.html#getParent()) method, which, in this case, might do the same. – Kamiccolo Apr 29 '14 at 15:43
Okay, that's a very constructive comment and that's positive. Lately, no idea why SO deducted user reputation without giving good reason. Lost my faith toward SO to actively contribute in the future. – Jasonw Apr 30 '14 at 04:31

score 0 · Answer 2 · answered Sep 13 '16 at 12:52

Try to specify the path of your image. For example:

Image picture = ImageIO.read(new File("C:/Desktop/picture.png"));

Or if the image is in your workspace, for example:

Image picture = ImageIO.read(new File("C:/workspace/Project/src/picture.png"));

You can see the image location (the path of your image) clicking with the right button of the mouse in the image, then Properties.

You can use one slah ( / ) or two backslashs ( \\ ) to separate the directories of the path.

score 0 · Answer 3 · answered Sep 13 '16 at 13:22

There is a dichotomy in java.

If your file is part of the deliverable project, a file which can be packed in the application jar file, then it is a resource.
```
Image picture = ImageIO.read(SomeClassOfYours.class.getResource("/picture.png"));
```

The path is relative to that class, and can be made an absolute path. All on the java class path of the application.

If your file is a file system file, a File, then the path best is a full absolute path. A relative path depends at which working directory the application is run, and that might differ.
```
Image picture = ImageIO.read(new File("C:/.../src/picture.png"));
```

The question seems to indicate that the image is a read-only part of the application, in which case it is a resource file. The path must be case sensitive, and the path separator must be a forward slash /.

score 0 · Answer 4 · edited Jan 12 '21 at 19:00

0

The ImageIO.read() function will check whether an image is corrupted or not. If it's corrupted, it will throw an exception.

ImageIO.read(new File("C:/Desktop/picture.jpeg"));

edited Jan 12 '21 at 19:00

Adrian Mole

49,934
160
51
83

answered Jan 12 '21 at 14:31

Chinna

1

Opening an image

4 Answers4