JSON String Will Not Parse

Question

I'm trying to parse a JSON string from a web service. The string that is coming in looks like this:

{
"Faculty_Members": [
    {
        "ID": 3377,
        "First_Name": "John",
        "Last_Name": "Doe"
    }
]
}

My IOS Code looks like this:

NSURL *jsonUrl = [NSURL URLWithString:@"http://website/Service1.svc/Names"];
NSError *error = nil;
NSData *jsonData = [NSData dataWithContentsOfURL:jsonUrl options:kNilOptions error:&error];
NSMutableDictionary *jsonResponse = [NSJSONSerialization JSONObjectWithData:jsonData options:NSJSONReadingAllowFragments error:&error];
NSLog(@"%@",jsonResponse);

//parse out the json data
if([NSJSONSerialization isValidJSONObject:jsonResponse])
{
NSLog(@"YEP");
  }else{
NSLog(@"NOPE");
}

The log will show the correct JSON data, but I keep getting "NOPE" on the isValidJsonObject.

The web service is sending the data back as datatype "string". Does that make a difference? If so, what datatype should i send it back?

Any ideas will be greatly appreciated!

i am try to parese same type of dic. and getting problem. @ NeedSomeAnswers if you get any solution and post it. — Ayaz, Nov 25 '13 at 13:12

score 3 · Answer 1 · answered Feb 28 '12 at 15:04

3

You don't use isValidJSONObject: to test for a valid JSON string, you use it to test for an object that can be converted to JSON; See the documentation:

isValidJSONObject:

Returns a Boolean value that indicates whether a given object can be converted to JSON data.
+ (BOOL)isValidJSONObject:(id)obj
Parameters:

obj

The object to test.

Return Value:

YES if obj can be converted to JSON data, otherwise NO.

Instead, just use JSONObjectWithData: to parse the data as usual; if it fails, it will return an NSError in error.

answered Feb 28 '12 at 15:04

Ry-

218,210
55
464
476

So, does that mean that an NSDictionary is not a valid object to parse with? – NeedSomeAnswers Feb 28 '12 at 15:08
@NeedSomeAnswers: I think it is; just make sure you pass the right options. – Ry- Feb 28 '12 at 15:18

score 0 · Answer 2 · answered Nov 22 '12 at 15:01

You should read up on JSON. { } indicates a dictionary. [ ] indicates an array

So your returned JSON object is a dictionary containing an array containing a dictionary. To get the content, you could try the following:

// YOUR CODE
NSURL *jsonUrl = [NSURL URLWithString:@"http://website/Service1.svc/Names"];
NSError *error = nil;
NSData *jsonData = [NSData dataWithContentsOfURL:jsonUrl options:kNilOptions error:&error];
NSMutableDictionary *jsonResponse = [NSJSONSerialization JSONObjectWithData:jsonData options:NSJSONReadingAllowFragments error:&error];
NSLog(@"%@",jsonResponse);

// MY ADDITIONS
NSArray *facultyMembers = [jsonResponse objectForKey:@"Faculty_Members"];
NSDictionary *facultyMember = [facultyMembers objectAtIndex:0];

or even

for(NSDictionary *dict in jsonResponse)
{
    // parse contents of dict; perhaps store in temp object and add to 
    // mutable dictionary or array
    NSNumber *ID = [dict objectForKey@"ID"];
    NSString *firstName = [dict objectForKey@"First_Name"];
    NSString *lastName = [dict objectForKey@"Last_Name"];
}

score 0 · Answer 3 · answered Feb 28 '12 at 15:08

0

It is also possible that the web service delivers the JSON strings in a wrong coding.

According to the NSJSONSerialization Class Reference!

The data must be in one of the 5 supported encodings listed in the JSON specification: UTF-8, UTF-16LE, UTF-16BE, UTF-32LE, UTF-32BE. The data may or may not have a BOM. The most efficient encoding to use for parsing is UTF-8, so if you have a choice in encoding the data passed to this method, use UTF-8.

answered Feb 28 '12 at 15:08

motou

726
4
12

Thanks motou. I tried the following code - NSLog(@"%@", [jsonResponse objectForKey:@"First_Name"]); but I get a message that says "unrecognized selector sent to instance". And when i look at the keys of my dictionary, it says that I have none. – NeedSomeAnswers Feb 28 '12 at 15:12
Can I encode is on the IOS side, or do i have to do it on the web service side? – NeedSomeAnswers Feb 28 '12 at 15:14

JSON String Will Not Parse

3 Answers3

isValidJSONObject:

Parameters:

Return Value: