How can i trigger a onFailure event for g:formRemote?

Question

I am using grails and i have a basic form remote

<g:formRemote name="add" onSuccess="close();" onFailure="dispayErrors();\"
                  url="[controller: ctx, action: 'insert']" method="POST" class="add">
 //Some inputs + submit button
</g:formRemote>

My question is what shoud the insert method return for so that onFailure is triggered? Thanx

there's no need to add a semicolon at the end of each `onXXX` attribute value — Dónal, Feb 20 '12 at 17:21

Dónal · Accepted Answer · 2012-02-20T16:49:36.583

2

Change the controller action (temporarily I presume) to

def insert = {
    render status: HttpServletResponse.SC_INTERNAL_SERVER_ERROR

    // This also works
    //response.sendError HttpServletResponse.SC_INTERNAL_SERVER_ERROR
}

If you're using Grails 2.0 it is recommended to define your action as a method rather than a closure:

def insert() {
    render status: HttpServletResponse.SC_INTERNAL_SERVER_ERROR
}

edited Feb 20 '12 at 16:49

answered Feb 20 '12 at 15:28

Dónal

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I didn't know methods were the preferred way of implementing actions in 2.0. For further reading: http://grails.org/doc/latest/guide/theWebLayer.html#understandingControllersAndActions – Jarred Olson Feb 20 '12 at 15:45

How can i trigger a onFailure event for g:formRemote?

1 Answers1