Filling an array with numbers sequentially

Question

I have a number (e.g. 6) that is dynamically generated and I would like to fill an array with the numbers 1 through the dynamically generated number (in this example, 6):

array(1, 2, 3, 4, 5, 6);

The only way I know to do this at the moment is by using a for loop, but I'm wondering if there's a better way, something similar to array_fill. I looked at array_fill, but it doesn't look like it will take a number and increment it for a set number of times.

score 42 · Accepted Answer · answered Feb 10 '12 at 20:47

42

Use range:

$arr = range(1,6);
// Returns an array of elements from start to limit, inclusive.

answered Feb 10 '12 at 20:47

Josh

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Perfect, Thanks! (I'll accept the answer in 6 minutes - didn't realize they have a minimum amount of time I have to wait from asking the question to marking it as answered). – Francis Lewis Feb 10 '12 at 20:53
@Francis No problem! Just happy to help. – Josh Feb 10 '12 at 20:57
If you want the keys to be the same as the values, you should combine this with array_combine: – Joe Bergevin May 27 '13 at 10:08
2

$num_range = range(1, 50); $resultNums = array_combine($num_range, $num_range); – Joe Bergevin May 27 '13 at 10:09

score 5 · Answer 2 · answered Feb 10 '12 at 20:47

5

This is what you are looking for:

range(1, 6)

answered Feb 10 '12 at 20:47

cEz

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Filling an array with numbers sequentially

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