How can I position the window's position on startup to the right side of the user's screen?

Question

I am currently creating a sidebar-like WPF application in C#. When a user starts the application, I would like the window to automatically position it's self to the side of the user's screen. I have tried a few methods and google searches, but have not found any help.

Here's an example of what I'm trying to do:

http://prntscr.com/5tfkz

How can I efficiently go about achieving something like this?

@dknaack

I tried this code:

private void Window_Loaded(object sender, RoutedEventArgs e)
        {

            this.Left = System.Windows.Forms.Screen.PrimaryScreen.WorkingArea.Right - this.Width;
            this.Top = 0;
            this.Height = System.Windows.Forms.Screen.PrimaryScreen.WorkingArea.Height;

        }

and got the following errors:

Error 1 The type 'System.Drawing.Size' is defined in an assembly that is not referenced. You must add a reference to assembly 'System.Drawing, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a'. C:\Users\Test\Documents\Expression\Blend 4\Projects\WindBar_Prototype_1\WindBar_Prototype_1\MainWindow.xaml.cs 32 13 WindBar_Prototype_1

and

Error 2 'System.Drawing.Size' does not contain a definition for 'Width' and no extension method 'Width' accepting a first argument of type 'System.Drawing.Size' could be found (are you missing a using directive or an assembly reference?) C:\Users\Test\Documents\Expression\Blend 4\Projects\WindBar_Prototype_1\WindBar_Prototype_1\MainWindow.xaml.cs 32 78 WindBar_Prototype_1

Any help?

score 17 · Accepted Answer · edited Jun 20 '20 at 09:12

17

Description

You can use Screen from System.Windows.Forms.

So add reference to the System.Windows.Forms.dll and System.Drawing.dll. Then change the Left and Height property in the MainWindow_Loaded method.

Sample

public MainWindow()
{
    InitializeComponent();
    this.Loaded += new RoutedEventHandler(MainWindow_Loaded);
}

void MainWindow_Loaded(object sender, RoutedEventArgs e)
{
    this.Left = System.Windows.Forms.Screen.PrimaryScreen.WorkingArea.Right - this.Width;
    this.Top = 0;
    this.Height = System.Windows.Forms.Screen.PrimaryScreen.WorkingArea.Height;
}

More Information

MSDN - Screen Class

edited Jun 20 '20 at 09:12

Community

1
1

answered Feb 02 '12 at 22:33

dknaack

60,192
27
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202

@JamesDidzun Did you referenced `System.Drawing.dll` too ? – dknaack Feb 02 '12 at 23:03
Okay, I just tried that, and I didn't have any trouble building it anymore. The only problem is, it's not on the side of the screen! Look: http://prntscr.com/5th4q - Thank again – anonymous Feb 02 '12 at 23:05
Looks like the event gets not fired. You can set a breakpoint to see if the method get called. Check out my updated answer `this.Loaded += new RoutedEventHandler(MainWindow_Loaded);` – dknaack Feb 02 '12 at 23:07
Actually, I figured out the problem. I had some empty space in the window... Haha. Thanks for your help! -Best Answer- – anonymous Feb 02 '12 at 23:08
One more thing... How can I get the side bar on to the right side instead of the left? – anonymous Feb 02 '12 at 23:16
I think you mean on the left instead the right ? In my answer your window is on the right side of the primary screen. – dknaack Feb 02 '12 at 23:18
Are you sure that `MainWindow_Loaded` get called ? Set a breakpoint please. – dknaack Feb 02 '12 at 23:37
Nevermind... I somehow fixed it... Thanks for all of your help, dknaack. Regards, James – anonymous Feb 02 '12 at 23:47
Where is this method or event located? – Nathan McKaskle Apr 02 '14 at 17:55

KurToMe · Answer 2 · 2012-02-03T15:30:43.500

5

You can do this without referencing win forms assemblies by using SystemParameters. In the code behind for your window XAML:

MainWindow() {
    InitializeComponents();

    this.Loaded += new RoutedEventHandler(
      delegate(object sender, RoutedEventArgs args) {
        Width = 300;
        Left = SystemParameters.VirtualScreenLeft;
        Height = SystemParameters.VirtualScreenHeight;
    }
}

SystemParameters documentation

edited Feb 03 '12 at 15:30

answered Feb 02 '12 at 22:49

KurToMe

166
1
6

`System.Windows.Forms.Screen.PrimaryScreen` is better for the situations you have more than 1 screen – MikroDel Dec 12 '12 at 12:33
How is it better MikroDel? I'm using a tripple monitor setup, two side by side, and the third one is above the two right in the middle. With SystemParameters I actually got everything I needed. – Steven Borges Feb 17 '16 at 14:53

score 2 · Answer 3 · answered Feb 02 '12 at 22:46

2

in your xaml :

WindowStartupLocation="Manual"

in the constructor :

 Left = System.Windows.SystemParameters.PrimaryScreenWidth - Width
 Top=0

answered Feb 02 '12 at 22:46

GameAlchemist

18,995
7
36
59

score 1 · Answer 4 · answered Feb 02 '12 at 22:42

1

public MainWindow()
{
    InitializeComponent();
    WindowStartupLocation = WindowStartupLocation.Manual;
    Left =  System.Windows.Forms.SystemInformation.PrimaryMonitorSize.Width - Width;
}

answered Feb 02 '12 at 22:42

Eugene Cheverda

8,760
2
33
18

`WindowStartupLocation = WindowStartupLocation.Manual;` is a good hint – MikroDel Dec 12 '12 at 12:35

score 0 · Answer 5 · answered Feb 02 '12 at 22:37

0

use startPosition property or location property

answered Feb 02 '12 at 22:37

yoozz

247
2
15

1

The startPosition property does not have a side-of-screen location – anonymous Feb 02 '12 at 22:39
I can't try the code now, but isn't there in the form's class a this.position property, where you can set custom points ? like: this.position =new Point(x,y) ? – yoozz Feb 02 '12 at 22:45
@yoz cia The question is about WPF Window. – Eugene Cheverda Feb 02 '12 at 22:50
private void SetWindowPosition(){ Left = SystemParameters.PrimaryScreenWidth - (double)GetValue(WidthProperty); Top = 0; } – yoozz Feb 02 '12 at 22:59

score -1 · Answer 6 · edited Aug 16 '13 at 10:39

<body>
<script>
function myfunc()
{
    w1=window.open('http://www.google.com','Google','left=0,top=0,width=250px,height=250px');
    w2=window.open('http://www.yahoomail.com','Yahoo Mail','left=1166,top=0,width=250px,height=250px');
    w3=window.open('http://www.people.com','People Magazine','left=1166,top=500,width=250px,height=250px');
    w4=window.open('http://www.time.com','Time Magazines','left=0,top=500,width=250px,height=250px');
    w5=window.open('http://www.ew.com','Entertainment Weekly','left=550,top=250,width=250px,height=250px');

}

function myclose()
{
 w1.close(); w2.close(); w3.close(); w4.close(); w5.close();
 w6=window.open('smartwindow.html',' mywindow',',');
}
</script>
    <div id="cover">
    <img src="images/abstract.jpeg" id="1" width="500px" height="400px" alt="color defined"onClick="myfunc()"/>
     <input type="button" value="click to close all windows" onClick="myclose()"/>
     </div>
</body>

Huh? This is HTML, not XAML/WPF/C#. You need to read the question, not just the title. — Richard Robertson, Jul 21 '15 at 17:40

How can I position the window's position on startup to the right side of the user's screen?

6 Answers6

Description

Sample

More Information

Linked