How to get all results if there are multiple matches : XSL

Question

I'm practicing some XSL and using this XML document as a simple example:

<?xml version="1.1" encoding="UTF-8"?>

<zoo xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:noNamespaceSchemaLocation="zoo.xsd" >
    <animals>
        <animal type="lion">
            <name>Zeus</name>
            <gender>M</gender>
            <eats>antelope</eats>
            <eats>monkey</eats>
        </animal>
        <animal type="monkey">
            <name>Fredo</name>
            <gender>M</gender>
            <eats>banana</eats>
            <iseatenby>lion</iseatenby>
        </animal>
        <animal type="lion">
            <name>Here</name>
            <gender>F</gender>
            <eats>antelope</eats>
            <eats>monkey</eats>
        </animal>
        <animal type="antelope">
            <name>Annie</name>
            <gender>F</gender>
            <eats>grass</eats>
            <iseatenby>lion</iseatenby>
        </animal>
        <animal type="elephant">
            <name>Moses</name>
            <gender>M</gender>
            <eats>leaves</eats>
        </animal>
    </animals>
</zoo>

I've been able to get some basic info via my XSL doc, but I'm stuck on one thing right now: how can I get all of the results if there are more than one? For example, in my document, some animals have multiple "eats" elements. I want to display them in a comma-separated string; eventually I want to transform each animal's elements into attributes and just have a single attribute for each. (Using my previous example, the new animal element lion's "eats" attribute would look like this: eats="antelope, monkey" )

Could someone please explain how I would do something like this with XSL?? Any help is much appreciated. :)

Answer 1

not a perfect though :)

try it now hope it helps .. I am converting each element as attribute ..

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
  <xsl:output method="xml" indent="yes"/>

  <xsl:template match="@* | node()">
    <xsl:copy>
      <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="//animal">
    <xsl:copy>
      <!--copies all other elements as attributes-->
      <xsl:for-each select="*[name()!='eats']">
        <xsl:attribute name="{name()}">
          <xsl:apply-templates select = "text()"/>
        </xsl:attribute>
      </xsl:for-each> 

      <xsl:attribute name="eats">

        <!-- Go to <eats/> node -->
        <xsl:for-each select="eats">

          <!--insearts string ", " if it has preceding values already :) -->
          <xsl:if test="preceding-sibling::eats">
            <xsl:text>, </xsl:text>
          </xsl:if>

          <!--copies all the text :) -->
          <xsl:apply-templates select="text()"/>

        </xsl:for-each>
      </xsl:attribute>
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>

Answer 2

Use this:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" indent="yes"/>

  <xsl:template match="zoo/animals">
    <xsl:copy>
      <xsl:apply-templates select="animal"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="animal">
    <xsl:copy>
      <xsl:attribute name="eats">
        <xsl:for-each select="eats">
          <xsl:value-of select="."/>

          <xsl:if test="position() != last()">
            <xsl:text>,</xsl:text>
          </xsl:if>
        </xsl:for-each>
      </xsl:attribute>
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>

Reference:

The position function returns a number equal to the context position from the expression evaluation context. The last function returns a number equal to the context size from the expression evaluation context.

xsl:if checks if the current node isn't last node in context. If so, outputs ,.

http://www.w3.org/TR/xpath/#function-last