Can't use javascript variable inside nested function (jquery masonry plugin)

Question

I want to use a javascript variable to calculate the columnWidth variable of the jQuery Masonry plugin. When I view source on my page, I see the variable name in the javascript rather than the variables value.

http://jsfiddle.net/robflate/fS2yL/

Thanks

Sorry you need to elaborate on this. What is the fiddle not doing that you want it to do? — mplungjan, Jan 28 '12 at 16:10
Your problem is that when you look at your source, you see " return containerWidth / columns; " and not " return containerWidth / 5; " ? — dievardump, Jan 28 '12 at 16:11

score 3 · Accepted Answer · answered Jan 28 '12 at 16:15

3

Javascript is intepreted... it's normal that you see "return containerWidth / columns;" in your source code.

When the javascript will be interpreted, the value of "columns" will be used.

If it does not work, it's surelly because you set "columns" as a string ( "5" ) and not as an integer. The division can't be perfomed.

answered Jan 28 '12 at 16:15

dievardump

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As I've just said in reply to another question relating to something similar, I'm sure everyone who knows that javascript doesn't update the source is thinking I must be stupid but I honestly never knew that. Thanks for the info and help. – robflate Jan 28 '12 at 17:47

score 0 · Answer 2 · answered Jan 28 '12 at 16:14

0

That is expected - source will show what you loaded, it won't change the values. See this jsfiddle:

http://jsfiddle.net/PFw9u/

This will work as expected.

answered Jan 28 '12 at 16:14

icyrock.com

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Can't use javascript variable inside nested function (jquery masonry plugin)

2 Answers2