Bash command substution error

Question

The code:

`cat <(fgrep -i -v "$DAEMON_TEST" <(sudo -u asm crontab -l)) <(echo "$CRON") | sudo -u asm crontab -`

The error:

command substitution: line 46: syntax error near unexpected token `('
/etc/init.d/asm: command substitution: line 46: `cat <(fgrep -i -v "$DAEMON_TEST" <(sudo -u asm crontab -l)) <(echo "$CRON") | sudo -u asm crontab -'

The command runs fine when run directly into the shell by replacing the variables with the relevant strings

Here are the variables:

DAEMON_TEST=asm_test.php
CRON="*/15 * * * * /opt/asm/daemons/test.php"

I'm not 100% sure what this command does but im 100% sure it shouldn't need this many command & process substitutions and pipes — SiegeX, Jan 26 '12 at 07:59
You have DAEMON_CONTROLLER as a variable and you are using DAEMON_TEST in the command sub? — jaypal singh, Jan 26 '12 at 08:01
Just a suggestion, you can replace `<(echo "$CRON")` with `<<< "$CRON` — jcollado, Jan 26 '12 at 08:01
It checks to see if DAEMON_TEST is found as a cron job, if it is, that line is replaced with CRON. If not, it is appended. — HyderA, Jan 26 '12 at 08:02
@Jaypal: I pasted in the incorrect variable, there is a variable called DAEMON_TEST.php — HyderA, Jan 26 '12 at 08:02
If I don't, I get the following syntax error `syntax error near unexpected token \`('` — HyderA, Jan 26 '12 at 08:13
What different do you do when running it on command line and inside your script? — jaypal singh, Jan 26 '12 at 08:26

score 1 · Accepted Answer · edited Mar 20 '17 at 10:18

1

The issue ended up being completely unrelated.

Changed:

#/bin/sh

to:

#/bin/bash

I never realized there would be a differnce

https://superuser.com/questions/125728/what-is-the-difference-between-bash-and-sh

edited Mar 20 '17 at 10:18

Community

1
1

answered Jan 26 '12 at 10:22

HyderA

20,651
42
112
180

1

Specifically, process substitution `<()` is not supported by `sh`. – Dennis Williamson Jan 26 '12 at 17:49

Bash command substution error

1 Answers1