using c# to create node in drupal

Question

i need to make a ("webservice") c# app that can create/update/delete nodes for/from drupal 7 using xmlrpc. everytime i run my app i get errors from the xmlrpc files(library). I tried to find code/documentation for C# using xmlrpc to connect to drupal, but in vain. I would be nice if you could point me in the right direction, or share some c# code with me.

{
[XmlRpcUrl("http://testing/testserver")]
public interface IDrupalServices
{
    [XmlRpcMethod("node.get")]
    XmlRpcStruct NodeLoad(int nid, string[] field);
    [XmlRpcMethod("node.save")]
    void NodeSave(XmlRpcStruct node);
}

public partial class Form1 : Form
{

    public Form1()
    {
        InitializeComponent();

        IDrupalServices drupal = XmlRpcProxyGen.Create<IDrupalServices>();

        int nid = 227;
        string[] fields = new string[] { };

        XmlRpcStruct node = drupal.NodeLoad(nid, fields);

        string teaser = node["teaser"].ToString();
        welcomeTxt.Text = teaser;
    }

    private void button1_Click(object sender, EventArgs e)
    {
        string title = txtTitle.Text;
        string body = txtBody.Text;

        IDrupalServices drupal = XmlRpcProxyGen.Create<IDrupalServices>();

        XmlRpcStruct node = new XmlRpcStruct();

        node["id"] = 1001;
        node["title"] = title;
        node["body"] = body;
        node["teaser"] = body;
        node["format"] = 1;
        node["type"] = "webservice";
        node["promote"] = false;

        drupal.NodeSave(node);
        MessageBox.Show("The post was been created!");

    }
}
}

After i run this i get the error: Server returned a fault exception: [-32601] Server error. Requested method node.get not specified. - in the XmlRpcSerializer.cs

Thank you, Florin

Please post sample code you've tried, and the actual error message you get. Check out http://tinyurl.com/so-hints — Mike Atlas, Jan 14 '12 at 21:35

Clive · Accepted Answer · 2012-01-15T19:44:07.460

3

If you're using Drupal 7 you must be using Services 3 which doesn't have a node.get method (or node.save as it happens). They've been replaced with node.retrieve and node.create & node.update respectively.

You can view all of the available methods in the resources/node_resource.inc file in the Services module folder.

UPDATE

Internally the node is submitted using drupal_execute which is the function used to submit a form. Since the body is a field in Drupal it's expected to be a multi-dimensional array in this format (PHP version):

$data["body"][$language][0]["value"]

The $language will either be the specific language for the node, or und for undefined language (unless you're dealing with a multi-lingual site und is usually the way to go). You'd need to build an array similar to that in your C# code and Drupal should save it.

ANOTHER UPDATE

The Java XML-RPC client example for Services uses a HashMap type to do this so my best guess is you could use a Dictionary (albeit one that seems unnecessarily complicated):

var innerValue = new Dictionary<string, string>();
innerValue.Add("value", txtBody.Text);

var language = new Dictionary<int, Dictionary<string, string>>();
language.Add(0, innerValue);

var body = new Dictionary<string, Dictionary<int, Dictionary<string, string>>>();
body.Add("und", language);

node["body"] = body;

It's been a few years since I've coded in C# so forgive any errors in there. Also I'm pretty sure it could be declared more efficiently but I've forgotten most of the language to be honest!

edited Jan 15 '12 at 19:44

answered Jan 14 '12 at 22:18

Clive

36,918
8
87
113

thank you, that worked.. but still i have a problem with the body of the node, if i add text to the node["body"] it won't appear. Can u tell me why? – Sergiu Jan 15 '12 at 10:37
@pretender: It's to do with the way Drupal expects fields on a node to be formatted (the body being a field in Drupal 7). I've updated the answer, hope it helps – Clive Jan 15 '12 at 13:40
i made an array [,,] but in vain. Could you share some code, if it's not too much to ask. i'll owe you one. thanks! – Sergiu Jan 15 '12 at 19:12
@pretender: I've had another go :) – Clive Jan 15 '12 at 19:44
thanks for the code:D the app runs but when i hit the button to create the node it gives and error in the XmlRpcStruct.cs --- System.Collections.Generic.Dictionary`2[System.String,System.Collections.Generic.Dictionary`2[System.Int32,System.Collections.Generic.Dictionary`2[System.String,System.String]]] cannot be mapped to an XML-RPC type – Sergiu Jan 15 '12 at 20:05
Thank you very much!!!! i managed to make it. Instead of dictionary i used XmlRpcStruct. works like a charm – Sergiu Jan 15 '12 at 20:16
Good stuff glad you got it sorted – Clive Jan 15 '12 at 21:21
Clive can u tell me how can i retrieve body from a specific node? thx! – Sergiu Jan 24 '12 at 09:58

score 0 · Answer 2 · edited Aug 16 '15 at 23:13

Jan's answer is not quite right. If you are using the cook xmlrpc library all you would need to do is this:

        XmlRpcStruct postStruct = new XmlRpcStruct();
        postStruct.Add("type", "article");
        postStruct.Add("title", "wohoo another test");

        XmlRpcStruct postBodyStructParams = new XmlRpcStruct();
        postBodyStructParams.Add("value", "My body yaaay");
        postBodyStructParams.Add("format", "filtered_html");

        XmlRpcStruct[] postBodyStructParamsArr = new XmlRpcStruct[1];
        postBodyStructParamsArr[0] = postBodyStructParams;

        XmlRpcStruct postBodyStruct = new XmlRpcStruct();
        postBodyStruct.Add("und", postBodyStructParamsArr);

        postStruct.Add("body", postBodyStruct);

Unfortunately, the body params need to be an array of struct under the "und" key with only one value. I blame this on the sloppiness of the drupal xmlrpc API.

using c# to create node in drupal

2 Answers2