calling a function with cherry.py

Question

So im doing a bit of web development, and due to some restriction set by my employer i need to use cheetah and cherrypy. I have this form that upon submit runs a function, and from said function i call another via HTTPRedirect, and what i want is to call it without redirecting. here is an example

@cherrypy.expose
def onSubmit(**kwargs):
  ##Do something
  ##Do something
  ##Do something

  raise cherrypy.HTTPRedirect("/some_other_location/doSomethingElse?arg1=x&arg2=y")

now i want to do more stuff after running the second function, but i cant because since i redirect the code ends there. So my question is, is there a way to run that other function and not redirect, but still using HTTP. In javascript i would use AJAX and pass it the url, storing the output on the loader variable, but im not sure how to do this with cherrypy

the second function is off limits to me, someone else design it and i'm not allowed to change it. — Lex, Jan 11 '12 at 17:07

score 2 · Accepted Answer · answered Jan 12 '12 at 06:00

Instead of doing the redirect, use one of the standard Python libraries for fetching HTTP data:

or other arguably nicer third-party ones:

Also, don't forget to convert the relative url to an absolute url, even if it's localhost:

To help you get started, here's an untested code snippet derived from your example, using urllib2:

import urllib2

@cherrypy.expose
def onSubmit(**kwargs):
  ##Do something
  ##Do something
  ##Do something

  url = "http://localhost/some_other_location/doSomethingElse?arg1=x&arg2=y"

  try:
    data = urllib2.urlopen(url).read()
  except urllib2.HTTPError, e:
    raise cherrypy.HTTPError(500, "HTTP error: %d" % e.code)
  except urllib2.URLError, e:
    raise cherrypy.HTTPError(500, "Network error: %s" % e.reason.args[1])

  ##Do something with the data

calling a function with cherry.py

1 Answers1