TypeError: 'int' object is not iterable

Question

I am trying to have a program look inside multiple lists to see if there are multiple integers in those lists. I received an answer on a previous question I asked to accomplish that task. However a problem arose with that answer and I can not figure out what it is.

Here is the code:

def all_num_in_list(d, numbers):
    for n in numbers:
        if n not in d:
            return False
    return True
def all_num_in_any_list(lists, numbers):
    for d in lists:
        if all_num_in_list(d, numbers):
            return True
    return False
while a:
    try:
        for c, row in enumerate(matrix):
            if 0 in row:
                print("Found 0 on row:", c, "index:", row.index(0))
                if 1 not in row:
                    if all(row[row.index(0)] != 1 for row in matrix):
                        if all_num_in_any_list([2, 3, 4, 5, 6, 7, 8, 9], [row, box1, all(row[row.index(0)])]):
                        if all(row[row.index(0)] != 1 for row in matrix):
                            print ("t")

The error that it draws is:

if all_num_in_any_list([2, 3, 4, 5, 6, 7, 8, 9], [row, box1, all(row[row.index(0)])]):
TypeError: 'int' object is not iterable

Why is this happening, how can it be avoided, and what exactly is this code doing?

Thanks

Answer 1

The first parameter to all_num_in_any_list, [2,3,4,5,6,7,8,9], is a single list, not a list of lists. When you iterate through it, d is 1, then d is 2, and so forth. When you pass d as the first parameter to all_num_in_list, it is trying to treat it as a list even though it is an integer.

Answer 2

Here is your matrix, from an earlier question

matrix = [
    [0, 0, 0, 5, 0, 0, 0, 0, 6],
    [8, 0, 0, 0, 4, 7, 5, 0, 3],
    [0, 5, 0, 0, 0, 3, 0, 0, 0],
    [0, 7, 0, 8, 0, 0, 0, 0, 9],
    [0, 0, 0, 0, 1, 0, 0, 0, 0],
    [9, 0, 0, 0, 0, 4, 0, 2, 0],
    [0, 0, 0, 9, 0, 0, 0, 1, 0],
    [7, 0, 8, 3, 2, 0, 0, 0, 5],
    [3, 0, 0, 0, 0, 8, 0, 0, 0],
    ]

And here is the methods:

def all_num_in_list(d, numbers):
    for n in numbers:
        if n not in d:
            return False
    return True

def all_num_in_any_list(lists, numbers):
    for d in lists:
        if all_num_in_list(d, numbers):
            return True
    return False

And since you in an earlier question used the numbers, 3,5 and 6 as examples to look at, here is how you check if these numbers are in the matrix above:

all_num_in_any_list(matrix, [3, 5, 6])

Which will return False, as none of the lists in your list of lists will have all these tree numbers, while for example:

all_num_in_any_list(matrix, [0, 1, 9])

will return True, as there is a list that includes these numbers.

Answer 3

all_num_in_any_list extacts elements from lists, which in this case are all integers; then, it passes each integer to all_num_in_list, which is expecting a list instead.

Answer 4

The statement for n in numbers in this code is causing the problem

def all_num_in_list(d, numbers):      
    for n in numbers:          
        if n not in d:              
            return False      
    return True

The Partial Traceback is

if n not in d
def all_num_in_list(d, numbers):
def all_num_in_any_list(lists, numbers):
if all_num_in_any_list([2, 3, 4, 5, 6, 7, 8, 9], [row, box1, all(row[row.index(0)])]):        
TypeError: 'int' object is not iterable

So in function all_num_in_any_list you are already iterating for d in lists over the list lists to get integers which is passed to all_num_in_list. But here while trying to compare n with an atom d, is where the Error Happened.

Think Over?

Did you intend to do an integer comparition like n != d instead of if n not in d .

Note::: Next Time please post the Complete Traceback