String java startsWith

Question

public class Test {

    public static void main(String[] args) throws Exception {


        String s1 = "/program/rest/user/forgotPwd/";
        String s2 = "/program/rest/user/forgetPwd/test";
        System.out.println(s1.startsWith(s2));
        System.out.println(s2.startsWith(s1));
    }
}

Both the cases print false. Any explanations?

you should voteup all the answers since everybody has given right answer. :) — dku.rajkumar, Jan 03 '12 at 12:30

score 4 · Accepted Answer · answered Jan 03 '12 at 12:13

4

The strings are not as identical as you think. The first string contains forgotPwd while the second contains forgetPwd.

answered Jan 03 '12 at 12:13

RoflcoptrException

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score 2 · Answer 2 · answered Jan 03 '12 at 12:18

2

because in 1st string you are having forgotPwd and in second forgetPwd . Difference is o and e

answered Jan 03 '12 at 12:18

dku.rajkumar

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score 1 · Answer 3 · answered Jan 03 '12 at 12:14

1

Your s1 is not a part of s2. forgotPwd

Check this.

String s1 = "/program/rest/user/forgotPwd/";
String s2 = "/program/rest/user/forgotPwd/test";
System.out.println(s1.startsWith(s2));
System.out.println(s2.startsWith(s1));

Output:

false
true

answered Jan 03 '12 at 12:14

Vaandu

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score 1 · Answer 4 · answered Jan 03 '12 at 12:14

1

case 1 is obvious.
case 2 is false because s1 has "forgot" and s2 has "forget".

answered Jan 03 '12 at 12:14

Gaurav

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score 1 · Answer 5 · answered Jan 03 '12 at 12:16

1

That's natural. Look closer at your strings.

String s1 = "/program/rest/user/forgotPwd/";
String s2 = "/program/rest/user/forgetPwd/test";

s1 has the word forgotPwd, s2 has forgetPwd. There is 1 letter difference.

answered Jan 03 '12 at 12:16

ArVan

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score 1 · Answer 6 · answered Jan 03 '12 at 12:18

1

You have a typo in s2 it says:

String s2 = "/program/rest/user/forgetPwd/test";

and it should say:

String s2 = "/program/rest/user/forgotPwd/test";

answered Jan 03 '12 at 12:18

Wilmer

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score -1 · Answer 7 · answered Jan 03 '12 at 12:15

-1

Maybe you could try specifying an index of the form

        "Foobar".startsWith("bar", 3)

which returns true. After checking your typos of course.

answered Jan 03 '12 at 12:15

seeker

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String java startsWith

7 Answers7