Server to amazon EC2 instance communication with python?

Question

I have this. But it only works locally. I always receive a connection timeout when I run the client. The port on the server is open to the default security group.

server.py:

import SocketServer

class MyTCPHandler(SocketServer.BaseRequestHandler):
    def handle(self):
        self.data = self.request.recv(1024).strip()
        print self.client_address
        print self.data
        self.request.send(self.data.upper())

if __name__ == "__main__":
    HOST, PORT = "", 9800
    server = SocketServer.TCPServer((HOST, PORT), MyTCPHandler)
    server.serve_forever()

client.py:

import socket
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.sendto('Hello, world\n'('host.ip',  9800))
data = s.recv(1024)
s.close()

score 1 · Accepted Answer · answered Dec 09 '11 at 15:24

1

On client you're using socket.SOCK_DGRAM which is UDP, yet you are using TCP server (which would be socket.SOCK_STREAM).

answered Dec 09 '11 at 15:24

vartec

131,205
36
218
244

score 0 · Answer 2 · answered Dec 09 '11 at 12:29

0

Looks like you're opening port 9800 but talking to port 9999

answered Dec 09 '11 at 12:29

Simon Whitaker

20,506
4
62
79

Very correct - I incorrectly wrote my example down. I'm very sorry, I've corrected it. – Glycerine Dec 09 '11 at 12:35

score 0 · Answer 3 · answered Dec 09 '11 at 15:08

The code works correctly.

Within the AWS console within the Networking and Security tab select Security Groups and within the default security profile under the 'inbound' tab - add your port to the list...

using a source of 0.0.0.0/0 will listen on all ports.

Server to amazon EC2 instance communication with python?

3 Answers3