proc_obj = -> proto { print proto; puts("World")}
puts proc_obj["Hi"]
puts proc_obj.call("Hello") #Is this is the same as above
please refer me to some link to demystify this ...
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pankajdoharey
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What is happening to that lambda is that you're calling its [] method, which causes the lambda to be executed with the argument "Hi". And yes, calling call is the same as calling [].
sepp2k
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How can i pass multiple arguments to lambda ? say proc.call("hello","konichiwa") – pankajdoharey Dec 05 '11 at 20:12
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@pankajdoharey Yes, like that. – sepp2k Dec 05 '11 at 20:57
