You can leverage lazy evaluation expression templates.
AFAIK bind expressions are precisely in that family (as are Boost Proto epxressions, Spirit Grammar parse expressions etc.).
Update finally got my act together. However, it only works with callable objects with overloaded operator(). I suppose you can use something like this as glue?
- I now show both C++03 and C++11 proofs-of-concept that might help get something of a glue functor built-up around this
- The C++03 is near equivalent (see the
// TODO
in the code)
- The C++03 version depends on Boost Typeof and Boost Bind (see Boost Utility doc for
result_of
for backgrounds on result types of polymorphic function objects)
- Both versions live on IdeOne
Here is a partial port of the C++11 demo (below) into C++03 + Boost:
#include <string>
#include <iostream>
#include <boost/bind.hpp>
#include <boost/typeof/typeof.hpp>
struct overloaded
{
typedef int result_type;
int operator()(const std::string& s) const { return 1; }
int operator()(double d) const { return 2; }
};
struct factory
{
template <typename T> struct result { typedef BOOST_TYPEOF_TPL(boost::bind(overloaded(), T())) type; };
template <typename T>
typename result<T>::type operator()(const T& t) const
{
return boost::bind(overloaded(), t);
}
};
int main()
{
overloaded foo;
// based on local bind expression:
BOOST_AUTO(unresolved, boost::bind(foo, _1));
std::cout << unresolved("3.14") << std::endl; // should print 1
std::cout << unresolved(3.14) << std::endl; // should print 2
// based on a factory function template
factory makefoo;
std::string str("3.14"); // TODO get rid of this explicit instanciation?
std::cout << makefoo(str)() << std::endl; // should print 1
std::cout << makefoo(3.14)() << std::endl; // should print 2
}
As a simple example, this should work alright:
#include <string>
#include <iostream>
#include <functional>
using namespace std::placeholders;
struct overloaded
{
int operator()(const std::string& s) const { return 1; }
int operator()(double d) const { return 2; }
};
template <typename T>
auto makefoo(const T& t) -> decltype(std::bind(overloaded(), t))
{
return std::bind(overloaded(), t);
}
int main()
{
overloaded foo;
// based on local bind expression:
auto unresolved = std::bind(foo, _1);
std::cout << unresolved(3.14) << std::endl; // should print 2
std::cout << unresolved("3.14") << std::endl; // should print 1
// based on a factory function template
std::cout << makefoo(3.14)() << std::endl; // should print 2
std::cout << makefoo("3.14")() << std::endl; // should print 1
}