Jersey URL forwarding

Question

Inside a Jersey REST method I would like to forward to an another website. How can I achieve that?

@Path("/")
public class News {

    @GET
    @Produces(MediaType.TEXT_HTML)
    @Path("go/{news_id}")
    public String getForwardNews(
        @PathParam("news_id") String id) throws Exception {

        //how can I make here a forward to "http://somesite.com/news/id" (not redirect)?

        return "";
    }
}

EDIT:

I'm getting the No thread local value in scope for proxy of class $Proxy78 error when trying to do something like this:

@Context
HttpServletRequest request;
@Context
HttpServletResponse response;
@Context
ServletContext context;

...

RequestDispatcher dispatcher =  context.getRequestDispatcher("url");
dispatcher.forward(request, response);

score 9 · Answer 1 · answered Nov 29 '13 at 20:44

9

public Response foo()
{
    URI uri = UriBuilder.fromUri(<ur url> ).build();
    return Response.seeOther( uri ).build();
}

I used above code in my application and it works.

answered Nov 29 '13 at 20:44

Ajai S

99
1
2

1

You can use Response.temporaryRedirect(location).build(); see full example here http://www.javaproficiency.com/2015/04/redirect-in-jersey.html – Anuj Dhiman Aug 15 '16 at 10:49
http://stackoverflow.com/a/25332038/419348 `seeOther` is some kind different with `temporaryRedirect`. One is `301`, and one is `302`. – AechoLiu May 17 '17 at 08:02
2

This is redirect not forward. – Monir May 24 '17 at 19:52

score 3 · Answer 2 · edited Mar 18 '13 at 19:13

3

Try this, it worked for me:

public String getForwardNews(

@Context final HttpServletRequest request,

@Context final HttpServletResponse response) throws Exception

{

System.out.println("CMSredirecting... ");

response.sendRedirect("YourUrlSite");

return "";

}

edited Mar 18 '13 at 19:13

Stedy

7,359
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answered Mar 18 '13 at 18:57

user2167877

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Dewfy · Answer 3 · 2011-11-23T16:23:46.407

2

I can't test it right now. But why not...

Step 1. Get access to HttpServletResponse. To do it declare in your service something like:

@Context
HttpServletResponse _currentResponse;

Step 2. make redirect

...
_currentResponse.sendRedirect(redirect2Url);

EDIT

Well, to call forward method you need get to ServletContext. It is can be resolved the same way as response:

@javax.ws.rs.core.Context 
ServletContext _context;

Now _context.forward is available

edited Nov 23 '11 at 16:23

answered Nov 23 '11 at 13:15

Dewfy

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I'm interested in a forward, not redirect. – Don Grem Nov 23 '11 at 15:31
@DorinGrecu just add how to get to context – Dewfy Nov 23 '11 at 16:24
@Derwy Please see my edited question, it doesn't work straight away. – Don Grem Nov 25 '11 at 08:25
ServletContext does not have a forward method. – Fabian May 22 '14 at 16:22
@Fabian - sure you right, I omit some stuff. You have to use `_context.getRequestDispatcher(path)#forward` – Dewfy May 28 '14 at 12:41

Jersey URL forwarding

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