I try to create a table where a row is looking like this:
|Text1|Text2|Button1|
As soon as the user clicks on the button I want to exchange the Button1 with tow textFields and another button... so a normal AJAX-request. I've tried to implement this, not sure if this is the correct way, let me know if I could to it in a completely other way :S
So what I've already done: In my hook_menu i link to a function that returns the data:
return theme ( 'my_theme_function', array (
'running' => true,
'form' => $database->getData ()
) );
What happens in the getData()-Function: I create the form using drupal_get_form(..).. returned from the given form is this:
$data = array (
'items' => $finder->getGamesToPlayForm ( $form_state ),
'#title' => 'Title'
);
the $finder returns the list of items I want to show in the table. So nothing special.
my_theme_function is set to use a template-file where I would like to show the whole stuff. This looks like this:
$header = array (
'Col1',
'Col2',
''
);
$rows = array ();
foreach ( element_children ( $formData ['items'] ) as $gameId ) {
$row = array ();
$row [] = drupal_render ( $formData ['items'] [$gameId] ['#col1'] );
$row [] = drupal_render ( $formData ['items'] [$gameId] ['#col2'] );
$row [] = drupal_render ( $formData ['items'] [$gameId] ['#form'] );
$rows [] = $row;
}
$output = theme ( 'table', array (
'header' => $header,
'rows' => $rows
) );
unset($formData['items']);
$output .= drupal_render_children ( $formData );
print $output
this way, everything is printed correct. But there are no "form"-tags, which stops my form from working..
So, any idea/hint how to solve this kind of problem? Probably I'm on the completely wrong way..
