How do I find whether a string has a carriage return by using the String.Contain function using its ascii character?

Question

In C#, how do I find whether a string has a carriage return by using the String.Contains function? The ascii for carriage return is 13.

Chr(13) is how a carriage return is represented in Visual Basic. How is a carriage return represented in C# using its ascii character and not "\r"?

if (word.Contains(Chr(13))  
{  
    .  
    .  
    .  
}

What is wrong with `"\r"` (or, if you want a `char`, `'\r'`)? — Richard, Nov 12 '11 at 17:23

score 24 · Answer 1 · answered Nov 11 '11 at 21:37

24

if (word.Contains(Environment.NewLine)) { }

answered Nov 11 '11 at 21:37

Joao

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5

No, that's "\r\n" on Windows. – Hans Passant Nov 11 '11 at 21:40
1

No, that's not the same. Environment.NewLine is usually (but not necessarily) a CRLF pair, i.e. char(13)+char(10). – Jeremy McGee Nov 11 '11 at 21:40
That would be checking for OS specific NewLine in windows it's CRLF and on my mac it's LF – James Kyburz Nov 11 '11 at 21:48
TBH I answered this way because I'm under the impression it's what the OP _should_ hear more than the answer he _wanted_ to hear. Either way he now has both answers :) – Joao Apr 21 '17 at 21:29

score 19 · Answer 2 · answered Nov 11 '11 at 21:39

19

Since you state that you don't want to use \r then you can cast the integer to a char:

if (word.Contains((char)13)) { ... }

answered Nov 11 '11 at 21:39

Mark Byers

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score 5 · Answer 3 · answered Nov 11 '11 at 21:38

5

You can enter a char value using single quotes

var s = "hello\r";

if (s.Contains('\r')) 
{

}

If it's easier to read, you can cast 13 to char

var s = "hello\r";

if (s.Contains((char)13)) 
{

}

answered Nov 11 '11 at 21:38

Russ Cam

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It's even easier to read with: const char CR = '\r'; if(s.Contains(CR)) { ... } – Olivier Jacot-Descombes Nov 11 '11 at 21:47
@Olivier - yes, that's a bit easier on the eye :) – Russ Cam Nov 11 '11 at 21:49

score 2 · Answer 4 · 2011-11-11T21:52:22.367

2

This is valid in all .NET versions:

if (word.Contains("\r"))
{
  ...
}

This is valid only from .NET 3.5:

if (word.Contains('\r'))
{
  ...
}

edited Nov 11 '11 at 21:52

answered Nov 11 '11 at 21:39

score 1 · Answer 5 · answered May 01 '19 at 13:50

1

I'm sure you can do this with a regular expression, but if you're dumb like me, this extension method is a good way to go:

public static bool HasLineBreaks(this string expression)
{
    return expression.Split(new[] { "\r\n", "\r", "\n" },StringSplitOptions.None).Length > 1;
}

answered May 01 '19 at 13:50

Mike Bruno

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Even though this works it's not optimal considering that it involves unnecessary string allocations. Having said that, for the sake of competeness I would also add the arcane "\f" (line feed) in the mix – XDS Aug 21 '23 at 14:58

score 1 · Answer 6 · answered Nov 11 '11 at 21:40

1

Convert.Char(byte asciiValue) creates a char from any integer; so

if (word.Contains(Convert.Char(13))

should do the job.

answered Nov 11 '11 at 21:40

Jeremy McGee

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score 1 · Answer 7 · answered Nov 11 '11 at 21:51

1

s.Contains('\x0D');

characters are represent using single quotes;

What's wrong with using \r ?

answered Nov 11 '11 at 21:51

James Kyburz

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How do I find whether a string has a carriage return by using the String.Contain function using its ascii character?

7 Answers7