Create BigInt with a String encoded to base 16

Question

I am trying to parse a String like this:

f2cff0a43553b2e07b6ae3264bc085a

into a BigInt however when using the String constructor for BigInt I obviously get a Number format exception:

BigInteger bi = new BigInteger("f2cff0a43553b2e07b6ae3264bc085a");

Any ideas how I can do this?

Thanks for your answers sorry it was an easy question, been a long day :) — SnowyTracks, Nov 09 '11 at 20:42

score 9 · Accepted Answer · answered Nov 09 '11 at 20:37

9

Use the radix parameter:

BigInteger bi = new BigInteger("f2cff0a43553b2e07b6ae3264bc085a", 16);

answered Nov 09 '11 at 20:37

Jonathon Faust

score 3 · Answer 2 · answered Nov 09 '11 at 20:37

3

Just use the constructor with the radix (using 16 as radix):

answered Nov 09 '11 at 20:37

JB Nizet

score 1 · Answer 3 · answered Nov 09 '11 at 20:43

I think you just need to specify that the string is in hexadecimal. Try

BigInteger bi = new BigInteger("f2cff0a43553b2e07b6ae3264bc085a",16);

3 Answers3