Given a file like the following:-
01/09/2005
02/09/2005
03/09/2006
03/09/2006
I wish to compare if the last two lines are the same, and return a 1 if so or a 0 if they are not.
I can get the last two using a cat tail -2
tail -n 2 filename.txt | uniq | wc -l
This will yield 1
for identical lines, 2
for different.
How about this:
lc=`wc -l filename.txt | cut -d " " -f1`
if [ $lc -ge 2 ]
then
ulc=`tail -n 2 filename.txt | uniq | wc -l`
if [ $ulc -eq 1 ]
then
echo "Last two lines are identical"
fi
fi
Try this
[ `cat | tail -n 2 | uniq | wc -l` -eq "1" ] && echo 1 || echo 0
Replace echo
by exit
to make it the exit value. Used echo
just for quicker testing.
#!/bin/bash
[ `cat | tail -n 2 | uniq | wc -l` -eq "1" ] && exit 1
exit 0
This might work for you:
sed -n '$!h;${G;/\(.*\)\n\1$/{s/.*/1/p;q};s/.*/0/p}' filename.txt