How to parse XML using XmlPullParser

Question

I want to use the Java XmlPullParser to parse an XML file like this:

<start>
    <tag1> text1 </tag1>
    <tag2> 
        <tag3>text3</tag3>
        <tag1>text4</tag1>
    </tag2>
    <tag4> text5</tag4>
</start>

I want only <tag1> text1 </tag1> as the result. My current method produces both <tag1> text1 </tag1> and <tag1>text4<tag1/>. What else must I do?

Edit:

I am getting the XML in String format. I want to parse it using org.xmlpull.v1.XmlPullParser;.

In the future, if you have a specific requirement (including but not limited to a particular parser), please mention it in the first draft of your question. — Pops, Nov 18 '11 at 22:25

score 9 · Answer 1 · answered Nov 04 '11 at 14:04

You could also just use the javax.xml.xpath APIs:

import java.io.FileReader;
import javax.xml.xpath.*;
import org.w3c.dom.Node;
import org.xml.sax.InputSource;

public class XPathDemo {

    public static void main(String[] args) throws Exception {
        XPathFactory xpf = XPathFactory.newInstance();
        XPath xpath = xpf.newXPath();
        InputSource xml = new InputSource(new FileReader("input.xml"));
        Node result = (Node) xpath.evaluate("/tag1", xml, XPathConstants.NODE);
        System.out.println(result);
    }

}

score 5 · Answer 2 · answered Nov 04 '11 at 14:23

5

Everyone has thier own preferences for XML processing in Java and my preference is to use JAXB when dealing with XML in Java because I find it easier to use that straight xpath.

answered Nov 04 '11 at 14:23

ChadNC

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I would still use JAXB with the only difference being that I would use a transform to save the xml string as an xml file then unmarshall the file into a Java object using JAXB and then get what I wanted from the object. – ChadNC Nov 07 '11 at 13:35

score 1 · Answer 3 · answered Nov 04 '11 at 14:04

1

You can do that using Java Xpath API

answered Nov 04 '11 at 14:04

hovanessyan

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score 0 · Answer 4 · answered Nov 04 '11 at 14:29

try to use dom4j library

    InputStream is = FileUtils.class.getResourceAsStream(filepath);
    SAXReader reader = new SAXReader();
    org.dom4j.Document doc = reader.read(is);
    is.close();
    Element content = doc.getRootElement();
    List<Element> els = content.elements("elemeNtname");

after this in method you will get in els list all the elements in xml file with name "elemeNtname".

How to parse XML using XmlPullParser

4 Answers4