How do you go about getting the contents portion of an RSS feed with Rome and Scala?

Question

I've been toying around with Rome 1.0 today with scala and while i've been able to get the title, description, etc tabs it says that getContent() doesn't exist.

   val url = "http://www.codecommit.com/blog/ruby/monads-are-not-metaphors/feed"
   val feed: SyndFeed = new SyndFeedInput().build(new XmlReader(new URL(url)))

   var rss_title = feed.getTitle()
   var rss_ex = feed.getTitleEx.getValue()
   var rss_desc = feed.getDescription()
   var rss_content = feed.getContent()  

<---- this one doesn't seem to exist though looking at the API it should work.

Answer 1

A feed represents multiple entries and the entries themselves have a getContents() method. Here's a complete working example (assumes you have rome 1.0 on the classpath):

import com.sun.syndication.feed.synd.{SyndContent, SyndEntry, SyndFeed}
import com.sun.syndication.io.{SyndFeedInput, XmlReader}
import java.net.URL
import java.util.{List => JList}
import scala.collection.JavaConverters._

object RomeApp extends App {
  val url = "http://www.codecommit.com/blog/ruby/monads-are-not-metaphors/feed"
  val feed: SyndFeed = new SyndFeedInput().build(new XmlReader(new URL(url)))
  val rss_title = feed.getTitle
  val rss_ex = feed.getTitleEx.getValue
  val rss_desc = feed.getDescription
  val rss_entries = feed.getEntries.asInstanceOf[JList[SyndEntry]].asScala
  for (entry <- rss_entries;
       content <- entry.getContents.asInstanceOf[JList[SyndContent]].asScala) {
    println("------------------------------")
    println(content.getValue)
  }   
}

Notice that the lack of generics in the Java API makes it a bit cumbersome to use, the library could use some pimping.