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Question

So for the first part, I simply figured as its a single packet, the new length would be F+H.

and since the speed between all links is R KB/S - then from start to the first router would be F+H/R.

Then I multiply this by number of links which is N - therefore a) is ((F+H)/R)*N

However for part b)

I tried splitting it up like so:

((F/P)+H) - new length of each segment,

((F/P)+H)/R - time taken for one segment to go from A to first router.

N*((F/P)+H)/R - time taken for one segment to reach B.

P*(N*((F/P)+H)/R - time taken for all segments to reach B.

This is somehow wrong and the correct answer is:

(N+P-1)*((F/P)+H)/R

Could someone help me out here.

Priit
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  • I have some problems with the question and answer. Some protocols have overhead other than the protocol header. For example, ethernet has a seven-octet Preamble, one-octet Start of Frame Delimiter, a four-octet Frame Check Sequence, and an eight-octet Inter-Packet Gap for each frame. Also, remember that you may have more than one frame at a time travelling on the same segment, albeit serially, where the first bit of the first frame has not reached the next hop before the first bit of the next frame is placed on the wire. – Ron Maupin Aug 27 '23 at 15:31

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