Exclusive OR in TypeScript

Question

so i want to know how to implement or exclusive in type script

my problem is I have two conditions a and b I want to enter if statement only if one of them correct and the other is not

what I have tried is this

if((a==false && b==true) ||  (a==true and b==false)){
DO SOMTHING }

but I want a more clean version

You can use [bitwise xor](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Bitwise_XOR). `true ^ false = true`, `true ^ true = false` — wonderflame, Jul 15 '23 at 14:01
Does this answer your question? [Why is there no logical XOR?](https://stackoverflow.com/questions/4540422/why-is-there-no-logical-xor) — kelsny, Jul 21 '23 at 15:09
@kelsny it's not only related to JavaScript, to TypeScript as well — Guerric P, Jul 21 '23 at 18:43

score 3 · Answer 1 · answered Jul 15 '23 at 14:16

3

TypeScript prevents using the bitwise XOR on boolean types, even if it would execute because JavaScript converts them to 0 and 1 on the fly. So just go for a !== b.

TypeScript playground

answered Jul 15 '23 at 14:16

Guerric P

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score 0 · Answer 2 · answered Jul 15 '23 at 14:02

If you are going to use this comparison a lot, you could refactor the expression in a xor function that would return this result

const xor = (a: boolean, b: boolean) => ((a && !b) || (!a && b));

If you're doing a one time and want to save some character space, go for bit manipulation if both a and b are booleans (https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Bitwise_XOR)

if(a ^ b) {
    // your stuff here
}

Though we could argue that bit manipulation might not be the most readable thing ever for someone that has never done it.

Exclusive OR in TypeScript

2 Answers2