Python replacing "\" character twice replace funtion

Question

I have text for fuzzy searching where user gives text, and I replace with characters used for regex parsing later.

Here is the text saved in configuration_blocks variable:

neighbor 10.1.(()).(())

Here is the code:

configuration_blocks = [sub.replace("$", ".*").replace("(())", "\S+") for sub in configuration_blocks]

However, the result is neighbor 10.1.\ \S with two backslashes.

How can I do this to get one backslash only?

Where do you see the result? – mkrieger1 Jul 12 '23 at 07:17 — mkrieger1, Jul 12 '23 at 07:17

Super MaxLv4 · Answer 1 · 2023-07-12T07:48:14.683

-1

If you want to use a single backslash in your string you need to escape it will another backslash like \. So in your code you do this:

configuration_blocks = [sub.replace("$", ".*").replace("(())", "\S+") for sub in configuration_blocks]

you might still get double backslash in the console but in the regex context, it will behave as the single backslash.

if you want to see the string as a single backslash in the console use raw text like this (r"")

edited Jul 12 '23 at 07:48

answered Jul 12 '23 at 07:23

Super MaxLv4

did you mean to add a double slash in the code above – hfakoor222 Jul 12 '23 at 07:28
oh sorry for the typo, please check the answer again – Super MaxLv4 Jul 12 '23 at 07:48
It worked. You were correct, the double slashS was read as \S when parsing the regex. – hfakoor222 Jul 13 '23 at 07:21
Glad to know, please upvote and tick the answer as correct if it worked for you. – Super MaxLv4 Jul 14 '23 at 05:20

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