Faking a service does not work. It calls the actual implementation of the service instead

Asked Jul 01 '23 at 19:17

Active Jul 01 '23 at 19:42

Viewed 45 times

I am faking a service using FakeItEasy

string phone = "123456";
var response = new VerifyResponse();
var fakeVerifyService = A.Fake<IVerifyService>();

var verifyCall = A.CallTo(() => fakeVerifyService.Verify(
                A<string>._,
                An<VerifyRequest>._));
//act
verifyCall.Returns(Task.FromResult(response ));
var result = await this.TestSubject.Handle(new VerifyPhoneCommand(phone), CancellationToken.None);
verifyCall.MustHaveHappened();

The problem here is that the implementation of IVerifyService.Verify is being called in the SUT method.

What am I doing wrong?

edited Jul 01 '23 at 19:42

asked Jul 01 '23 at 19:17

Isaac Ikusika

You define `fakeVerifyService` but used `fakeVerificationService` in the lambda. Is that correct? – Mustafa Özçetin Jul 01 '23 at 19:32
it’s a mistake i have corrected. – Isaac Ikusika Jul 01 '23 at 19:43
The code does not show `fakeVerifyService` being provided to `this.TestSubject`. I suspect you are not using `fakeVerifyService` in your test subject. – Blair Conrad Jul 01 '23 at 21:13
1

true. Thank you @BlairConrad – Isaac Ikusika Jul 01 '23 at 21:49

Faking a service does not work. It calls the actual implementation of the service instead

0 Answers0