I need to pass the YouTube video url and need to get all the available download format of that video.
(I'm achieving this using the ydlp.extract_info(url, download=False) method.)
Then from the all available formats, I need to filter and select a particular format. for example, I need a video with resolution=720p, video without audio type and extension=webm. (For this, I'm filtering the results of ydlp.extract_info(url, download=False) and selecting the particular format)
Now, I need to pass this selected format to a function and download the video. And I also need to pass the output filepath & filename.
I tried, ydlp.process_ie_result method but I'm getting an error while running.
import yt_dlp
ydlp = yt_dlp.YoutubeDL()
url = 'https://www.youtube.com/watch?v=d95PPykB2vE'
video_info = ydlp.extract_info(url, download=False)
formats = video_info['formats']
# selecting a random format for now
formats = formats[5]
ydlp.process_ie_result(formats, download=True)
But if I run this program, I getting this error,
raise ExtractorError('Missing "id" field in extractor result', ie=info_dict['extractor'])
~~~~~~~~~^^^^^^^^^^^^^
KeyError: 'extractor'
I'm using yt-dlp version 2023.06.22
In pytube we can,
- get all available streams for a video
- filter a selected stream that we need to download and
- download that stream.
Basically I'm trying to achieve this using yt-dlp
