Failed to define the target at build.zig

Question

I'm at linux and want to cross compile for windows, I've the below that is working file for building the executable at linux:

pub fn build(b: *std.build.Builder) void {

    const target = b.standardTargetOptions(.{});

    // const target = "x86_64-windows";


    const mode = b.standardReleaseOptions();

    const exe = b.addExecutable("Zig", "src/main.zig");
    exe.setTarget(target);
    exe.setBuildMode(mode);
    exe.install();
}

I tried to use const target = "x86_64-windows"; but it failed telling that error: expected type 'zig.CrossTarget', found '*const [14:0]u8'

Why not just use the `-Dtarget=` option when invoking `zig build`? — ad absurdum, Jun 20 '23 at 15:03

score 2 · Accepted Answer · answered Jun 20 '23 at 15:20

2

you need to pass a CrossTarget.

const target = std.zig.CrossTarget{ .os_tag = .windows, .cpu_arch = .x86_64 };

also as @ad-absurdum said you can just run zig build -Dtarget=x86_64-windows

answered Jun 20 '23 at 15:20

Ali Chraghi

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Failed to define the target at build.zig

1 Answers1