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I have made code below. i want correct value as 44112.25895 but result value is 44112.3 how can i fix this issue?

QJsonObject qj{ {"close", 44112.25895} };
qDebug() << qj;
QJsonValue qjv = qj.value("close");
qDebug() << qjv;
qDebug() << qjv.toDouble();

result is

QJsonObject({"close":44112.25895})

QJsonValue(double, 44112.3)

44112.3

Pamputt
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steven cn2018
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    Why do you think the value has not the correct valuie? You're using a debug helper function to print a value - if you want another precission you can e.g. print it with std::cout and the desired std::precision – chehrlic Jun 02 '23 at 05:32

2 Answers2

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As indicated by chehrlic in the comments, the default precision of qDebug() is not what you want. The Qt documentation says that the default precision is 6 digits.

You can adjust it using qSetRealNumberPrecision, like this:

 qDebug() << qSetRealNumberPrecision( 10 ) << qjv.toDouble();

If you want to set this precision only once, then you can define your own qDebug, such as:

#define qDebug10() qDebug() << qSetRealNumberPrecision(10)

and use it like this:

qDebug10() << qSetRealNumberPrecision( 10 ) << qjv.toDouble();
Pamputt
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It's only qDebug()'s representation issue.

Try this:

qDebug() << QString::number(qjv.toDouble(), 'f', 5);

You get: 44112.25895

Then, try:

qDebug() << QString::number(qjv.toDouble(), 'f', 30);

Now you get: 44112.258950000003096647560596466064

It's a floating point issue.

Benjamin Buch
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Nome
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