join random number of lines untill close brace match in unix file

Question

Need to join random number of lines untill close brac match and substitute with one space in unix file . There can be multiple occurence like this in file . One liner awk , sed , perl solution will be more helpful.

Eg :
....
abc_mod #(
.h_res(3),
.s_res(10)
)
u_abc_mod
(
....
....
....
def_mod #(
.lp(4),
.clk(9),
.add(5),
.d(8),
.por(1)
)
u_def_mod
(
....

Need to match pattern equivalent to #( till 1st close brace at starting of line ) followed by one extra new line (can include random number of lines ) and substitute with single space.

Desired Output :
....
abc_mod u_abc_mod
(
...
def_mod u_def_mod
(
...
...

Thanks

Using what tool? `sed`? `awk`? And remember that you can't match "till 1st close brace", because you have multiple parens inside there. You'll need to match until "line that starts with closed paren". — Tim Roberts, May 16 '23 at 05:25
Thanks , Edited ! Any tool is fine untill the required output is available . — argha chakraborty, May 16 '23 at 05:28
Can you please share using sed or awk or pcregrep/egrep , as it can be easily incorporated into csh script — argha chakraborty, May 16 '23 at 06:19
Regarding "... incorporated into csh script" - see https://www.grymoire.com/unix/CshTop10.txt, http://www.faqs.org/faqs/unix-faq/shell/csh-whynot/, etc. for why not to write scripts in csh. — Ed Morton, May 17 '23 at 14:16

score 1 · Answer 1 · answered May 16 '23 at 05:37

Here's a Python solution:

import sys

skip = False
for line in sys.stdin:
    line = line.rstrip()
    if not skip:
        i = line.find('#(')
        if i >= 0:
            print(line[:i], end='')
            skip = True
        else:
            print(line)
    else:
        if line == ')':
            skip = False

Output:

$  python x.py < x.tzt
abc_mod u_abc_mod
(
....
....
....
)
def_mod u_def_mod
(
....
)

join random number of lines untill close brace match in unix file

1 Answers1