I typed is digit function for user input, but when I enter an alphabet, it accepts the value

Question


            IDcheck = input("Enter The Customer ID ")
            if IDcheck.isdigit :
                print("Your ID is Being Searched")

            elif IDcheck.isalpha :
                print("IDs Only Contains Numbers")

I made a code to search customers names by ID . typed isdigit function to make sure the user enters a number but when I type a letter, it does accept it. why

Does this answer your question? [Python how to only accept numbers as a input](https://stackoverflow.com/questions/27516093/python-how-to-only-accept-numbers-as-a-input) — bonCodigo, May 07 '23 at 03:35
`.()` is be of your help.... and check on unicode char inputs too.. — bonCodigo, May 07 '23 at 03:39

score 1 · Accepted Answer · answered May 07 '23 at 03:45

String.isdigit is a function.

When the interpreter executes the line if IDcheck.isdigit: it checks if a function or variable called IDcheck.isdigit exists. IDcheck.isdigit exist and it returns True. The same applies to IDcheck.isalpha.

To fix this: change IDcheck.isdigit and IDcheck.isalpha to IDcheck.isdigit() and IDcheck.isalpha() by adding parentheses, as in:

IDcheck = input("Enter The Customer ID ")
if IDcheck.isdigit():
    print("Your ID is Being Searched")

elif IDcheck.isalpha():
    print("IDs Only Contains Numbers")

I typed is digit function for user input, but when I enter an alphabet, it accepts the value

1 Answers1