So here is my code:
void sigHandle(int sig)
{
signal(SIGINT, sigHandle); //Is this line necessairy?
cout<<"Signal: "<<sig<<endl;
}
int main(){
signal(SIGINT, sigHandle);
while(true){ //Supposed to loop until user exits.
//rest of my code
}
}
Now it is my understanding of signal() that when the SIGINT command (Ctrl+C right?) is received my function sigHandle should be called with an integer value of 2 (the SIGINT number), the method should run and the program should NOT exit.
All I would like to do is just print the signal number and move on, however after printing out "Signal: 2" it exits.
(Eventually I'm supposed to handle the first 32 interrupts but I figured Ctrl+C would be the most difficult so I'm starting here.)
In main if I do signal(SIGINT, SIG_IGN); it ignores the signal correctly and doesn't exit but I now have no way of knowing if I recieved the SIGINT interrupt.
Earlier I was playing around with the sigaction struct but I could not find any real comprehensive documentation on it so I decided to go with just "raw" signal handling.
This was my sigaction code (same problem as above):
struct sigaction action;
action.sa_handler = sigHandle;
sigemptyset(&action.sa_mask);
action.sa_flags = 0;
sigaction(SIGINT, &action, 0);
Thanks for your help!
EDIT
OK SO After many many many hours of scowering through man pages and the internet I have happened across a (very) ghetto solution involving saving the stack pre-infinite loop then when the interrupt comes, doing what I need to do, then re-setting the stack back to where it was and calling the sigrelse() command to re-set any states that might have been changed and not re-loaded.
I understand that this is not the most elegant/efficient/or even socially acceptable solution to this problem but it works and as far as I can tell I am not leaking any memory anywhere so it's all good...
I am still looking for a solution to this problem and I view my stack re-setting shenanigins as only a temporary fix...
Thanks!