How to get a list of all parents in directory that their children are files in python?

Question

I have a tree of directories that in the end of the each directory will always be 2 files, one as suffix ".txt" and one will always be ".jpg", for example: "rootFolder/a/a.txt", "rootFolder/a/b.jpg" "rootFolder/b/c/a.txt", "rootFolder/b/c/b.jpg" and I want that the output will be: ["rootFolder/a", "rootFolder/b/c"]

import pathlib
root = pathlib.Path("/rootFolder")
paths = list(root.rglob("*.txt")) + list(root.rglob("*.jpg"))

this code give me the pathes of the files but i want their parents and i'm pretty sure that i there is one line code that do it but i didn't figure it out.

What did you use to try and get the parent of a file from that file's path? — Scott Hunter, Apr 17 '23 at 17:13
I want to do it with one simple line that catch all and i get all the files and not their parents — Dump Eldor, Apr 17 '23 at 17:14

score 1 · Answer 1 · answered Apr 17 '23 at 17:21

1

So, just use dirname to remove the filename part of the path, and convert it to a set to remove duplicates:

paths = set([os.path.dirname(p) for p in paths])

answered Apr 17 '23 at 17:21

Tim Roberts

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thank you i used set([p.parent.absolute() for p in paths]) and it workes – Dump Eldor Apr 17 '23 at 17:25

How to get a list of all parents in directory that their children are files in python?

1 Answers1