IndexError in Python?

Asked Apr 04 '23 at 08:23

Active Apr 04 '23 at 08:25

Viewed 17 times

I was trying to write a function that accepts a list of integers as the parameter and then returns the list back with only positive integers (in the same order they were before) but I keep getting an index error.

def filter_positive_list(raw_data):
    le=len(raw_data)
    for i in range(le):
        if raw_data[i]<0:
            raw_data.pop(i)
        else:
            pass
data = [-3, -2, -1, 0, 1, 2, 3]
filter_positive_list(data)
print(data)

edited Apr 04 '23 at 08:25

khelwood

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asked Apr 04 '23 at 08:23

cherishroby

run for loop as `for i in range(le-1, -1, -1):`.. – Yash Mehta Apr 04 '23 at 08:25
1

By the time you get to the end of your loop, your list is shorter because you have removed some elements, so your loop runs off the end of the list. – khelwood Apr 04 '23 at 08:27
@cherishroby You can simply use filter method to filter out negative numbers:-> data = list(filter(lambda x: x>0, data)) – Bhavesh Rathod Apr 04 '23 at 08:33
@BhaveshRathod If you are using a lambda in filter then there is no reason to use filter in the first place. Just use a list comprehension: `[n for n in raw_data if n > 0]` – Lecdi Apr 04 '23 at 08:37
That's right @Lecdi.! – Bhavesh Rathod Apr 04 '23 at 08:43

IndexError in Python?

0 Answers0