Using awk to get nameserver info from nslookup

Question

Hello I am trying to pull the ns records for a few domains we own. I want to script it so the data is formatted in domain name, ns record, ns record, ns record domain name, ns record, ns record, ns record domain name, ns record, ns record, ns record

What I am getting is

domain name, ns record, ns record, ns record ns record, domain name, ns record, ns record ns record, ns record, domain name, ns record

here is the command I have got so far but it organises in alphabetic order.

Input

cat dom.txt
domain1.com
domain2.com
domain3.com

awk '{print}' < dom.txt | while read domain; do nslookup -type=ns $domain | grep nameserver | sed -e 's/nameserver =//g' -e 's/.$//' | awk '{print $1 "\n" $2}' | sort -u | tr '\n' ',' | sed -e 's/,$//' | awk '{print}'; done

Please take a look at [How to create a Minimal, Complete, and Verifiable example](http://stackoverflow.com/help/mcve). — Cyrus, Mar 21 '23 at 21:47

Gilles Quénot · Accepted Answer · 2023-03-22T01:43:09.220

On way, using dig and shell: tested mostly bourne* bash, dash, ash, yash, ksh, zsh, sh (but not csh & fish compliant):

$ cat dom.txt 
example.org
w3c.org
gnu.org

$ while read domain; do
      echo "$domain,$(dig +short NS "$domain" | paste -sd ',')"
  done < dom.txt

Output

example.org,a.iana-servers.net.,b.iana-servers.net.
w3c.org,ns-139-c.gandi.net.,ns-225-a.gandi.net.,ns-206-b.gandi.net.
gnu.org,ns3.gnu.org.,ns2.gnu.org.,ns1.gnu.org.

Using awk to get nameserver info from nslookup

1 Answers1

Output