Java Printf - N places of decimals

Question

I want to format my decimal number output, so that it has N amount of decimal space.

For certain amount of places I know you can just do

System.out.printf("%.2f",number);

but I want to do something like

System.out.printf("%.(%d)f",spaces,number);

So basically the same output but the number of decimal space changes based on the input (the user determines amount of decimal space). I understand that line doesn't work but I don't know other ways to do this.

Please check out [this answer](https://stackoverflow.com/a/38122245/522444) — Hovercraft Full Of Eels, Mar 13 '23 at 13:29
Why not just take the user input as an int like `int numberOfDecimalPlaces = scanner.nextInt();` and then just do `System.out.printf("%." + numberOfDecimalPlaces + "f",number);` — OH GOD SPIDERS, Mar 13 '23 at 13:29
Note that what @OHGODSPIDERS is showing you is what is shown in the answer in my link above. — Hovercraft Full Of Eels, Mar 13 '23 at 13:29

WJS · Answer 1 · 2023-03-13T19:37:49.797

0

Try it like this.

% escapes % so %% formats a single %.
formatted does the same thing as String.format()
After formatted is done, the format string will be %.2f%n

int n = 2;
double value = 3.88833; 

System.out.printf("%%.%df%n".formatted(n), value);

prints

3.89

edited Mar 13 '23 at 19:37

answered Mar 13 '23 at 13:32

WJS

36,363
4
24
39

Java Printf - N places of decimals

1 Answers1